Answer:
The graph of g is translated down 5 units from the graph of f and stretched horizontally
Step-by-step explanation:
was correct on test :)
pls brainliest XD
.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.
First write both vectors in terms of their horizontal and vertical components.
G = (40.3 m)(cos(-35.0º) x + sin(-35.0º) y)
G = (33.0 x - 23.1 y) m
(where x and y are the unit vectors that point in the positive horizontal and vertical directions, respectively)
H = (63.3 m)(cos 270º x + sin 270º y)
H = (-63.3 y) m
Then the vector sum is
G + H = (33.0 x - 86.4 y) m
which has a magnitude of
|| G + H || = √[33.0^2 + (-86.4)^2] = 92.5 m
The answers should be about 9 minutes and 2.4 seconds.
Answer:
The last one.
Step-by-step explanation:
The standard form equation of an ellipse with foci on the y-axis is ...
y²/a² +x²/b² = 1
where "a" and "b" are the lengths of the semi-major and semi-minor axes, respectively. If "c" is the distance from the center to the focus, then this relation also holds:
b² +c² = a²
For this ellipse ...
b² + 8² = 17²
289 -64 = b² = 225 . . . . . subtract 8²
b = 15 . . . . . . . . . . . . . . . . . take the square root
The equation of the ellipse is then ...
y²/17² +x²/15² = 1
Answer:V
Step-by-step explanation:
im going to guess c = degrees and its always the angle with a higher degree