Answer: the answer is animalia and plantae
Explanation: I just took the test.
Answer:
Limiting reactant is NiSO₄
Explanation:
The reaction of aluminum metal with aqueous nickel(II) sulfate to produce aqueous aluminum sulfate and nickel is:
2 Al(s) + 3 NiSO₄ → Al₂(SO₄)₃ + 3 Ni
<em>That means 2 moles of Al react with 3 moles of nickel sulfate.</em>
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Moles of Al and NiSO₄ are:
Al: 108g × (1mol / 26.98g) = 4.00 moles of Al
NiSO₄: 464g × (1mol / 154.75g) = 3.00 moles of NiSO₄
For a complete reaction of aluminium there are necessary:
4.00mol Al ₓ ( 3 moles NiSO₄ / 2 moles Al) = 6 moles of NiSO₄
As you have just 3.00 moles of NiSO₄, the <em>limiting reactant is NiSO₄</em>
There are three measures of retrieval and forgetting, bear in mind, the degree to which a person brings found facts back to conscious cognizance; recognition.
A measure in which someone identifies previously discovered statistics; and relearning, a measure wherein a person is asked to learn facts at a time. There are five popular theories of forgetting in psychology. they are the hint decay principle, retrieval failure idea, interference theory, consolidation concept, and displacement idea.
In keeping with retrieval-failure theory, forgetting happens whilst statistics are available in LTM but aren't accessible. Accessibility relies upon in massive part on retrieval cues. Forgetting is finest whilst context and country are very one-of-a-kind at encoding and retrieval.
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Answer:
1.33 Å
Explanation:
Given that the edge length , a of the KCl which forms the FCC lattice = 6.28 Å
Also,
For the FCC lattice in which the anion-cation contact along the cell edge , the ratio of the radius of the cation to that of anion is 0.731.
Thus,
.................1
Also, the sum of the radius of the cation and the anion in FCC is equal to half of the edge length.
Thus,
...................2
Given that:
To find,
Using 1 and 2 , we get:
<u>Size of the potassium ion = 1.33 Å</u>
Answer:- 5.199 moles.
Solution:- To do the conversion from number of particles to moles, we use Avogadro number. Given number of particles is divided by Avogadro number and we get the moles.
Avogadro number is . The calculations are given below:
= 5.199 moles
So, there would be 5.199 moles in particles.