All categories

3 years ago

How many atoms are in 1.50 moles of Hg?

Chemistry

2 answers:

Oxana [17]3 years ago

3 0

Answer:

Atoms=9.033*10^23 atoms

Explanation:

Atoms=no.of miles*Avogadro's no.

Atoms=1.5*6.022*10^23

Atoms=9.033*10^23 atoms

vesna_86 [32]3 years ago

3 0

Answer:

There are 9.0345*10²³ in 1.5 moles of Hg.

Explanation:

The Avogadro Number or Avogadro Constant is called the number of particles that constitute a substance (usually atoms or molecules) and that can be found in the amount of one mole of that substance. Its value is 6.023 * 10²³ particles per mole. Avogadro's number applies to any substance.

Then a rule of three can be applied to calculate the number of atoms in 1.5 moles of Hg. This rule applies as follows: if 1 mole of Hg contains 6,023 * 10²³ atoms, 1.5 moles how many atoms of the element will they contain?

$Number of atoms=\frac{1.5 moles* 6.023*10^{23}atoms }{1 mole}$

Number of atoms=9.0345*10²³

<u><em>There are 9.0345*10²³ in 1.5 moles of Hg.</em></u>

You might be interested in

Use Appendix C to choose the solution with the lower pH:0.1MBeCl₂ or 0.1MCaCl₂

musickatia [10]

A lower pH means that there are extra hydrogen ions in the liquid, whereas a higher pH indicates fewer hydrogen ions in the liquid. In simple terms, pH is a scale from 1 to 14 that measures the acidity or alkalinity of a liquid.

The hydrated ion undergoes hydrolysis in solution producing `H3O+ . This occurs because the Be-O bond is very strong and so in the hydrated ion and it weakens the 0-H bond. Hence, there is a strong tendency to lose protons. For this particular reason, the aqueous solution of `BeCl_2` is acidic in nature.

<h3>Will baking soda decrease pH?</h3>

Baking soda, also regarded as sodium bicarbonate is naturally alkaline, with a pH of 8 When you add baking soda to your pool water, you will increase both the pH and the alkalinity, improving balance and clarity. Many industrial pool merchandise for elevating alkalinity utilize baking soda as their most important active ingredient.

Learn more about pH here:

<h3>brainly.com/question/22390063</h3><h3 /><h3>#SPJ4</h3>

6 0

11 months ago

Do you really get 7 years of bad luck if you crack a mirror :(

Mazyrski [523]

Answer:

nope its a myth don't worry :)

4 0

2 years ago

Please help!! Balancing Nuclear Equations

sineoko [7]

The missing part of the equation is found to be 4/2He. Option A

<h3>What are nuclear equations?</h3>

The term nuclear equations have to do with the type of equation in which one type of nucleus is transformed into another sometimes by the bombardment or loss of a particle.

Now the full equation ought to be written as 7/3Li + 1/1H -----> 4/2He + 4/2He. This is because the total mass on the left is 8 and the total charge on the left is 4.

Learn more about nuclear equations:brainly.com/question/19752321

#SPJ1

8 0

2 years ago

Which is more metallic<br><br> a) Silicon<br><br> b) Aluminum

Alekssandra [29.7K]

Answer:b

Explanation:

4 0

3 years ago

Read 2 more answers

What is the concentration of a solution containing 1.11 g sugar (sucrose, C12H22O11, MW = 342.3 g/mol, d = 1.587 g/cm3) in 432 m

djyliett [7]

Answer:

0.0075 M

0.0060 m

Explanation:

Our strategy here is to use the definition of molarity and molality to solve this question.

The molarity is the number of moles of solute, sucrose in this case, per liter of solution.

The molality is the number of moles of solute per kilogram of solvent.

So the molarity of the solution is

M = moles of solute/ V solution

As we see we need the volume of solution since we are only given the volume of solvent, but this will be easy to compute since we have the density of sucrose.

So determine the moles of sucrose , and the volume of solution:

Moles sucrose = 1.11 g/342.3 g/mol = 3.24 x 10⁻³ M

Volume of solution = Vol Sucrose + Vol glycerine

d = m/V ⇒ Vsucrose = m / d = 1.11 g/ 1.587 g/cm³ = 0.70 cm³

Vol solution = 432 mL + 0.70 mL = 432.7 mL (1cm³ = 1 mL)

Vol solution = 432.7 mL x 1 L / 1000 mL = 0.4327 L

⇒ M = 3.2 x 10⁻³ mol / 0.4327 L = 0.0075 M

For the molarity what we need is to first calculate the kilograms of glycerine from the given density:

d = m/v ⇒ m = d x v = 1.261 g/cm³ x 432 cm³ = 544.75 g

Converting to Kg:

544.75 g x 1 Kg/ 1000 g = 0.544 kg

Now the molality is

m = mol sucrose/ kg solvent = 3.24 x 10⁻³ mol / 0.544 Kg = 0.0060 m

Note: In the calculation for volume of solution we could have approximated it to that of just glycerine, but since the density of sucrose was given we calculated the total volume of solution to be more rigorous.

8 0

3 years ago