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3 years ago

Yo i said i ned help lolololololo

Mathematics

1 answer:

Alexus [3.1K]3 years ago

3 0

Answer:

9.125

Step-by-step explanation:

9.25 - 1/2 + 3/8 =

= 9.25 - 0.5 + 0.375

= 8.75 + 0.375

= 9.125

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The average weight of a male African elephant is 15,000 pounds. How many tons is this?

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Answer:

7.5 tons

Step-by-step explanation:

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2 years ago

Read 2 more answers

You have received an order of 100 robotic resistance spot welders which contains 5 defective welders. You randomly select 15 wel

erica [24]

Answer:

$P(X = 0) = h(0,100,15,5) = \frac{C_{5,0}*C_{95,15}}{C_{100,15}} = 0.4357$

$P(X = 1) = h(1,100,15,5) = \frac{C_{5,1}*C_{95,14}}{C_{100,15}} = 0.4034$

$P(X = 2) = h(2,100,15,5) = \frac{C_{5,2}*C_{95,13}}{C_{100,15}} = 0.1377$

$P(X = 3) = h(3,100,15,5) = \frac{C_{5,3}*C_{95,12}}{C_{100,15}} = 0.0216$

$P(X = 4) = h(4,100,15,5) = \frac{C_{5,4}*C_{95,11}}{C_{100,15}} = 0.0015$

$P(X = 5) = h(5,100,15,5) = \frac{C_{5,5}*C_{95,10}}{C_{100,15}} = 0.00004$

b) 0.154% probability that there are at least 4 defective welders in the sample

Step-by-step explanation:

The welders are chosen without replacement, so the hypergeometric distribution is used.

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

100 welders, so $N = 100$

Sample of 15, so $n = 15$

In total, 5 defective, so $k = 5$

(a) Determine the PMF of the number of defective welders in your sample?

There are 5 defective, so this is P(X = 0) to P(X = 5). Then

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,100,15,5) = \frac{C_{5,0}*C_{95,15}}{C_{100,15}} = 0.4357$

$P(X = 1) = h(1,100,15,5) = \frac{C_{5,1}*C_{95,14}}{C_{100,15}} = 0.4034$

$P(X = 2) = h(2,100,15,5) = \frac{C_{5,2}*C_{95,13}}{C_{100,15}} = 0.1377$

$P(X = 3) = h(3,100,15,5) = \frac{C_{5,3}*C_{95,12}}{C_{100,15}} = 0.0216$

$P(X = 4) = h(4,100,15,5) = \frac{C_{5,4}*C_{95,11}}{C_{100,15}} = 0.0015$

$P(X = 5) = h(5,100,15,5) = \frac{C_{5,5}*C_{95,10}}{C_{100,15}} = 0.00004$

(b) Determine the probability that there are at least 4 defective welders in the sample?

$P(X \geq 4) = P(X = 4) + P(X = 5) = 0.0015 + 0.00004 = 0.00154$

0.154% probability that there are at least 4 defective welders in the sample

5 0

3 years ago

Geneva's younger brother has a toy box that is 3.6 feet

Anestetic [448]

Answer:

12.96 ft ³

Step-by-step explanation:

3 0

3 years ago

Julie's first three test scores in biology were 65, 90 and 73. What was her average score?

dedylja [7]

Answer:Julie's average score was 76

Step-by-step explanation:

The formula for Average or mean is expressed as

Average = sum of terms / total number of terms.

Julie's first three test scores in biology were 65, 90 and 73.

The sum of the scores would be

65 + 90 + 73 = 228

The number of terms is the number of subjects. Therefore, the number of terms is 3. Therefore,

Average = 228/3 = 76

6 0

4 years ago

Is this correct? |-4+5i| √-4²+5² √-16+25 √-9 =3

melamori03 [73]

No it is not, √-9=3i

5 0

3 years ago