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IgorC [24]
3 years ago
5

A class of 50 students elected a class president. Candidate received 15 votes. Candidate B received 2525 votes. The remaining st

udents did not vote. Which expression gives the percent of voters who voted for Candidate B?
Mathematics
1 answer:
Marianna [84]3 years ago
5 0

Answer:

x= 25/15+25= 0.625 (62.5%)

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PLEASE BE CAREFUL NightmareMech14 IS A PREDATOR HE ASKS FOR VIDEOS OF GIRLS AND TRYS TO GET THEM TO EMAIL HIM DONT GIVE HIM ANY INFORMATION STAY SAFE COPY AND PASTE THIS EVERYWHERE

Step-by-step explanation:

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2 years ago
The volume of clay used to build a cylindrical pillar with a height of 9 centimeters is 324π cubic centimeters. The area of the
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Area=height times base (for some prisms including cylinders)
vcylinder=hpir²
h=height
therefor pir²=base area
vcylinder=height times aeraofbase

 

given
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324pi=9(basearea)
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3 years ago
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Unit 3 Mid - Assessment
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Y=1x-7 is the equation and -7 is the value of B
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Equation for the points (3,8) (2,6) on slope
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\frac{8-6}{3-2} = \frac{2}{1}=4

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Plug in a point to solve for b
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The National Cancer Institute estimates that 3.65% of women in their 60s get breast cancer. A mammogram can typically identify c
masha68 [24]

Answer:

39.17% probability that a woman in her 60s who has a positive test actually has breast cancer

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Positive test.

Event B: Having breast cancer.

3.65% of women in their 60s get breast cancer

This means that P(B) = 0.0365

A mammogram can typically identify correctly 85% of cancer cases

This means that P(A|B) = 0.85

Probability of a positive test.

85% of 3.65% and 100-95 = 5% of 100-3.65 = 96.35%. So

P(A) = 0.85*0.0365 + 0.05*0.9635 = 0.0792

What is the probability that a woman in her 60s who has a positive test actually has breast cancer?

P(B|A) = \frac{0.0365*0.85}{0.0792} = 0.3917

39.17% probability that a woman in her 60s who has a positive test actually has breast cancer

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