What is the volume? 12ft 15ft 7ft

Natalie drives from her home to the art museum. She knows that when she passes the fire station,

scoundrel [369]

Answer:

is it maryann or natalie lol

Step-by-step explanation:

7 0

3 years ago

Five thousand three hundred nine divided by forty three

Marizza181 [45]

123.4651163 or rounded to 123.47

4 0

4 years ago

When 6 times a number is increased by 11 the result is 16 less than 9 times the number. Find the number.

scZoUnD [109]

Answer:

Brainly.in

Question

When 6 times a number  is increased by 11 the result is 16 less than 9 times the number. Find the number.

Answer · 7 votes

Answer:6x+11=9x-163x=27X=9 Please mark it brainliest

Step-by-step explanation:

Please mark it brainliest

5 0

2 years ago

True or false is a relation in which each y value has only 1 x value

boyakko [2]

Answer:

The statement is true that a function is a relation in which each y value has ONLY 1 x value.

Step-by-step explanation:

The statement is true that a function is a relation in which each y value has ONLY 1 x value.

The reason is very clear that we can not have the repeated x-values (two same x-values).

For example, given the set of the ordered pairs of a relation

{(3, a), (6, b), (6, c)}

As the same x values (x=6) has two different Y values. Hence, the stated relation is not a function.

In order to be a function, a relation must have only 1 x-value for each y-value.

Therefore, the statement is true that a function is a relation in which each y value has ONLY 1 x value.

5 0

3 years ago

GRE Test: The Graduate Record Examination (GRE) is a test required for admission to many US graduate schools. Student’s scores o

Zepler [3.9K]

Answer:

a) $\bar X=144.3$

b) The 95% confidence interval would be given by (138.846;149.754)

c) n=34

d) n=298

e) n=1190

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We can calculate the sample mean with this formula:

$\bar X = \frac{\sum_{i=1}^n x_i}{n}$

$\bar X=144.3$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=8.8$ represent the population standard deviation

n=10 represent the sample size

a) Find a point estimate of the population mean

We can calculate the sample mean with this formula:

$\bar X = \frac{\sum_{i=1}^n x_i}{n}$

$\bar X=144.3$

b) Construct a 95% confidence interval for the true mean score for this population.

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $t_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$144.3-1.96\frac{8.8}{\sqrt{10}}=138.846$

$144.3+1.96\frac{8.8}{\sqrt{10}}=149.754$

So on this case the 95% confidence interval would be given by (138.846;149.754)

Part c

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =+20 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (5) we got:

$n=(\frac{1.960(8.8)}{3})^2 =33.05 \approx 34$

So the answer for this case would be n=34 rounded up to the nearest integer

Part d

$n=(\frac{1.960(8.8)}{1})^2 =297.493 \approx 298$

So the answer for this case would be n=298 rounded up to the nearest integer

Part e

$n=(\frac{1.960(8.8)}{0.5})^2 =1189.97 \approx 1190$

So the answer for this case would be n=1190 rounded up to the nearest integer

7 0

3 years ago