Ask question

Ask question

All categories

3 years ago

6

if a boat that travels 37 miles per hour in still water is traveling with a current that has a rate of 3 miles per hour, how far

will the boat travel in 5 hours? ANSWERS:180 miles, 200 miles, 196 miles, 211 miles

1 answer:

egoroff_w [7]3 years ago

7 0

Answer:

200

Step-by-step explanation:

37+3=40

40×5=200

Write that down

You might be interested in

Find the circumstance of the circle

Karolina [17]

Answer:

72.22

Step-by-step explanation:

Circumference = πd

In your case, 3.14×23

$3.14*23=72.22$

5 0

4 years ago

Read 2 more answers

How do I solve 130 divided by 1.5

stepan [7]

The answer is 86.7.
When you calculate this, it will give you 86.666666667. You have to round it to only one decimal so since the 6 is bigger than 5, it turns into a 7.

8 0

3 years ago

Maggie filled the glasses shown below completely with water. The total amount of water that Maggie poured into the glasses is 12

Svetllana [295]

I think the answer is 7.47

6 0

3 years ago

What is the answer for 4x + 2y = 12

sesenic [268]

Answer:

(1,4), (2,2) (3,0)

Step-by-step explanation:

adjust the equation so that the y is isolated so subtract 4 x

2y=4x +12

Every number is divisible by 2 so you can further isolate the y

y=-2x+6

Plug your x coordinates into the equation so get the y coordinates

6 0

4 years ago

Read 2 more answers

A small radio transmitter broadcasts in a 30 mile radius. If you drive along a straight line from a city 33 miles north of the t

Paha777 [63]

Answer:

34.26miles from 49.58miles of the drive (69.11% of the drive).

Step-by-step explanation:

A problem of Analytic Geometry. This question can be solved using the resulting values from equaling the equations of the line (for the drive) and circle (with radius equals 30miles for radio transmitter broadcasting), and calculating the total distances from coincident points between circle and line, and total drive.

A graph is attached showing part of the circle and line with coincident points.

<h3>Line's Equation</h3>

Assuming transmitter is located (0, 0). From a city 33 miles north of the transmitter (0, 33) to a second city 37 miles east of the transmitter (37, 0).

Then, the equation for the line is (taking the two points from the start to the end):

$\\ y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}*(x-x_{1})$

$\\ y-33=\frac{0-33}{37-0}*(x-0)}$

$\\ y-33=\frac{-33}{37}*x}$

$\\ y=\frac{-33}{37}*x} + 33$ [1]

<h3>Circle's Equation</h3>

The equation for the circle whose center (0, 0) is:

$\\ (x-0)^2 + (y-0)^2 = 30^2$

$\\ x^2 + y^2 = 30^2$

$\\ y^2 = 30^2 - x^2$

$\\ y = \frac{+}{-}\sqrt{30^2- x^2}$ [2]

Equaling [1] and [2], to determine the points where starting to receive the radio transmitter signals to the point where finishing those signals:

$\\ \frac{-33}{37}*x + 33 = \sqrt{30^2- x^2}$

Solving this equation for <em>x</em>, we have two solutions for it (from <em>WolframAlpha</em>):

$\\ x_{1} = 40293/2458 - (111 \sqrt(80151))/2458 \approx 3.60775$

$\\ x_{2} = 40293/2458 + (111 \sqrt(80151))/2458 \approx 29.1774$

Then, using [1], the corresponding values for <em>y</em> are:

$\\ y_{1}=\frac{-33}{37}*(3.60775) \approx 29.78$

$\\ y_{2}=\frac{-33}{37}*(29.1774) \approx 6.97$

So,

$\\ (x_{1}=3.61, y_{1}=29.78)$

$\\ (x_{2}=29.18, y_{2}=6.97)$

Well, the distance of the drive is:

$\\ d = \sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2}$

$\\ d = \sqrt{(29.18-3.61)^2 + (6.97-29.78)^2}$

$\\ d \approx 34.2654$ miles.

The total distance traveled is:

$\\ d = \sqrt{(37-0)^2 + (0-33)^2}$

$\\ d \approx 49.5782$ miles

Thus, during the drive, the signal of the radio transmitter was picked up for 34.26miles from the total of the 49.58 traveled, that is, a fraction equivalent to $\\ \frac{34.2654}{49.5782} \approx 0.6911$ or 69.11% of the drive.

4 0

3 years ago