Answer:
a). Mileage for carA=
, and mileage for carB=
b).total mileage for both is similar to average of them= 
=![\frac{5x+4}{2x(x+1)}[tex]mil/gal](https://tex.z-dn.net/?f=%5Cfrac%7B5x%2B4%7D%7B2x%28x%2B1%29%7D%5Btex%5Dmil%2Fgal)
Step-by-step explanation:
It is given that the distance traveled by car 
And distance traveled by car 
We know the mileage is mile/gallon,
a).So mileage of car

Similarly , the mileage for car


b).total mileage for both is similar to average of them= 

Now divide by 2 for total(average) mileage.
.
Thus those are the answers.
You just plug in the values.
[3*(-2)]^3 - (-2 - 4*5)^2
(-6)^3 - ( - 2 - 20)^2
-216 - (-22)^2
-216 - (484)
-216 - 484
-700
Answer:
-3.85
-3 is a whole number, it comes before the decimal point.
17/20 is a fraction so it goes on the other side.
Inital value= 35,000
depreciation value= .10 or 10%
value after 4 yrs= 22,963.5