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densk [106]
3 years ago
13

Enter the number that belongs in the green box

Mathematics
2 answers:
Fofino [41]3 years ago
6 0

Answer:

x = 96 and y = 84

Step-by-step explanation:

Given

A Point

Angles x,y and 84 degrees

Required

Find x and y

First, we should note that angle x and 84 degrees are supplementary.

<em>Two angles are said to be supplementary if they add up to 180 degrees</em>

<em>i.e. x + 84 = 180</em>

x + 84 = 180

Make x the subject of formula

x = 180 - 84

x = 96

In the similar vein, angle x and y are supplementary.

so, x + y = 180

Substitute 96 for x

So, we have

96 + y = 180

make y the subject of formula

y = 180 - 96

y = 84

Hence, x = 96 and y = 84

OLga [1]3 years ago
5 0

Answer:

x=96°

y=96°

Step-by-step explanation:

y=84° because of vertical angles. the measure of all 4 angles added together is 360°, so we add the 84° and the other 84° angle, and subtract them from 360° to get the sum of the other two angles

360°-(84°+84°)=192°

divide 192° by 2 to get the measure of one angle

therefore, x=96°

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Read 2 more answers
How do you factor 125-x^3?
xz_007 [3.2K]

Step-by-step explanation:

We have

125 - x {}^{3}

First, 125 is a perfect cube because

5 \times 5 \times 5 = 125

and

x^3 is a perfect cube because

x \times  x \times x = x {}^{3}

so we can use the difference of cubes identity

( {x}^{3}  -  {y}^{3} ) = (x - y)( {x}^{2}  + xy +  {y}^{2} )

Let say we have two perfect cubes:

64 because 8×8×8=64

and 27 because 3×3×3=27 and let subtract

64 - 27

we know that

64 - 27 = 37

but using the difference of cubes identity we should get the same thing.

Remeber cube root of 64 is 4 and cube root of 27 is 3 so we have

(4 - 3)( {4}^{2}  + 4(3) + 3 {}^{2} )

1(16 + 12 + 9) = 1(37) = 37

So the difference of cubes works for real numbers. This is a good way to help remeber the identity using real numbers.

Back on to the topic,

we know that 5 is cube root of 125 and x is the cube root of x^3 so we have

(5 - x)( {5}^{2}  + 5x +  {x}^{2} ) =

(5 - x)(25 + 5x +  {x}^{2} )

3 0
2 years ago
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<img src="https://tex.z-dn.net/?f=81-%28y-1%29%28y%5E2%2B27%29%20%5Cgeq%200%20%5C%5C%5C%5C%2081-%28y%5E3%2B27y-y%5E2-27%29%20%5C
Zarrin [17]
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The other method is using Newton's method, it is similar to this but with a twist because it involves differentiation, so </span>y_{n+1}=y_n-\frac{f(y)}{f'(y)}<span> where 'n' is the number you approximate, like n=0,1,2... etc. f(y) would the equation, and f'(y) is the derivative of f(y), now what you'll need to do is substitute the 'n' values into 'y' to find the approximation.</span>
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