Answer:
n := length(A)
repeat
swapped := false
for i := 1 to n-1 inclusive do
<em> /* if this pair is out of order */</em>
if A[i-1] > A[i] then
<em> /* swap them and remember something changed */</em>
swap(A[i-1], A[i])
swapped := true
end if ⇒
end for
until not swapped
end procedure

Explanation:
This is pseudocode
The answer is A B AND D mark me brainliest?
Answer:
B from you search question carefully and identify the key word
Explanation:
Answer:
All of them execpt five and three.
Explanation:
It is okay to have social media and receive messages.