The designer could use the measurements in pixels.
Answer:
Consider the following code.
Explanation:
save the following code in read_and_interp.m
function X = read_and_interp(s)
[m, n] = size(s);
X = zeros(m, 1);
for i = 1:m
if(str2num(s(i, 2:5)) == 9999)
% compute value based on previous and next entries in s array
% s(i, 2:5) retrieves columns 2-5 in ith row
X(i,1) = (str2num(s(i-1 ,2:5)) + str2num(s(i+1,2:5)))/2;
else
X(i,1) = str2num(s(i,2:5));
end
end
end
======================
Now you can use teh function as shown below
s = [ 'A' '0096' ; 'B' '0114' ; 'C' '9999' ; 'D' '0105' ; 'E' '0112' ];
read_and_interp(s)
output
ans =
96.000
114.000
109.500
105.000
112.000
<span>The RAID level 2 could give high
information exchange rates and would be straightforward contrasted with other
Raid levels. Be that as it may, it has a high cost and would need a high rate move
required with a specific end goal to legitimize this cost.</span>
Answer:
this would be .128 terabytes
Explanation:
This would be since for a whole terabyte you need 1000 gigabytes every 1000 gigabytes is a terabyte for example let’s say you have 5250 gigabytes you would have 5.250 terabytes that simple hope this helped!
