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3 years ago

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A blue-faced Oompah (homozygous) is married to an orange-faced Oompah. They have 8 Oompah children. How many of these children w

ill have blue faces?

1 answer:

Shtirlitz [24]3 years ago

4 0

<span>Which one is dominant? If blue is dominant, then all the children would have blue faces, but be carriers of the alternate allele.</span>

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Sergeu [11.5K]

Line 1
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To find the slope:
M = (y - y) / (x - x)
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Line 2

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M = (y - y) / (x - x)
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4 years ago

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Hence the length of Olivia's lunch box shall be 'x + 2'

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Subtracting 80 from both sides

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3 3/4 is the answer.

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