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kumpel [21]
3 years ago
10

Please help!! Xoxo! Appreciate it :)

Mathematics
2 answers:
Degger [83]3 years ago
8 0

Answer:

B   x = sqrt(41)

Step-by-step explanation:

Since the large triangle is isosceles, the smaller triangles on the right side and left side are congruent right triangles.

The base of each smaller right triangle is 4 units long (8/2 = 4).

The vertical leg is 5.

Use the Pythagorean theorem to find x.

a^2 + b^2 = c^2

4^2 + 5^2 = x^2

16 + 25 = x^2

x^2 = 41

x = sqrt(41)

Answer: B   x = sqrt(41)

VLD [36.1K]3 years ago
6 0

Answer

B

Explanation

To find the value of x, you need to use the Pythagorean theorem.

x^{2} + y^{2} = z^{2}

x is one of the legs.

y is another one of the legs.

z is the hypotenuse (the longest side of a right triangle).

Now for this we can set 5 to be x and 4 to be y.

y is 4 because 4 is half of 8. We need to find half of 8 because the right triangle is half of the whole triangle.

Now 'plug' these into the formula and find z.

5^{2} + 4^{2}  = 41^{2}

To find z then we must find the square root of 41.

So the answer is B.

(Now I just realized that I used the variable z for the hypotenuse when you were supposed to be finding x for the hypotenuse but whatever).

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Alona [7]

Answer:

\large\boxed{1.\ (4)^{-3x^2}=\left(\dfrac{1}{4}\right)^{3x^2}}

\large\boxed{2.\ ab^{-3x}=a\left(\dfrac{1}{b}\right)^{3x}=a\left[\left(\dfrac{1}{b}\right)^3\right]^x}

Step-by-step explanation:

Use:\ a^{-n}=\left(\dfrac{1}{a}\right)^n\\------------\\\\(4)^{-3x^2}=\left[(4)^{-1}\right]^{3x^2}=\left(\dfrac{1}{4}\right)^{3x^2}

Use:\ a^{-n}=\left(\dfrac{1}{a}\right)^n\ and\ (a^n)^m=a^{nm}\\--------------------\\\\ab^{-3x}=a\cdot b^{-3x}=a\left[(b)^{-1}\right]^{3x}=a\left(\dfrac{1}{b}\right)^{3x}\\\\ab^{-3x}=a\left(\dfrac{1}{b}\right)^{3x}=a\left[\left(\dfrac{1}{b}\right)^3\right]^x

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