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2 years ago

How many three-person relay teams can be chosen from six students?

Mathematics

2 answers:

oksano4ka [1.4K]2 years ago

6 0

2 because 6 divided by 3 is 2

hope i helped

GenaCL600 [577]2 years ago

5 0

Divide 6 evenly so you would get 3 groups of 2 so 2 three person relay teams can be chosen from 6 students

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. How long does it take hair to grow 8 inches?

Veronika [31]

First of all, I do not see the need for the very long pause before the question. It just makes people like me have a harder job answering. But ok, here we go.

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For the second question:

If you would like to know how much a 93-pound person weighs on the Moon, you can calculate this using the following steps:

120 pounds on the Earth ... 20 pounds on the Moon

93 pounds on the Earth ... x pounds on the Moon = ?

120 * x = 20 * 93 /120

x = 20 * 93 / 120

x = 15.5 pounds on the Moon

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3 0

3 years ago

En las olimpiadas matemáticas,la hora de inicio del evento se expresa en una ecuación simple: 2x+6=x+17 ¿A qué hora empezó el ev

Sergio [31]

Answer:

11 minutos.

Step-by-step explanation:

En las Olimpiadas de Matemáticas, la hora de inicio del evento se expresa en una ecuación simple: 2x + 6 = x + 17 ¿A qué hora comenzó el evento?

La hora en que comienza el evento en los juegos olímpicos se representa como x

Por tanto: 2x + 6 = x + 17

Recopilar términos similares

2x - x = 17 - 6

x = 11 minutos

Por lo tanto, los eventos comienzan en 11 minutos.

7 0

2 years ago

Justin weighted 8lb 12oz when he was born at his two week check-up he had gained 8oz what was his new weight in pounds and ounce

avanturin [10]

The answer is 9 lbs and 4 oz

5 0

2 years ago

Read 2 more answers

AB=2y+1, BC=y+1,CD=7x-3,DA=3x what is x and y

sattari [20]

I attached the picture associated with this question.

Answer:
x = 2
y = 5

Explanation:
ABCD is a parallelogram. This means that each two opposite sides are equal.
This means that:
1- AB = CD
2y + 1 = 7x - 3 ...........> equation I
2- AD = BC
3x = y + 1
This can be rewritten as:
y = 3x - 1............> equation II

Substitute with equation II in equation I and solve for x as follows:
2y + 1 = 7x - 3 ...........> equation I
2(3x - 1) + 1 = 7x - 3
6x - 2 + 1 = 7x - 3
6x - 1 = 7x - 3
7x - 6x = -1 + 3
x = 2

Substitute with x in equation I to get y as follows:
y = 3x - 1
y = 3(2) - 1
y = 6 - 1
y = 5

Hope this helps :)

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Mazyrski [523]

70 mph
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2 years ago

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