Given: BD is an altitude of triangle ABC.
1 answer:
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Answer:
The correct answer is option A.
Step-by-step explanation:
Given : line AB intersect CD at P. PR is perpendicular to AB.
∠APD = 170°
To find = ∠DPB =?
Solution :
line AB intersect CD at P:
So,∠APD =∠BPC = 170° ..[1]
(vertically opposite angles of two straight lines intersecting at common point are equal)
On line CD two angles are ∠BPC ,∠DPB
∠BPC + ∠DPB =180° (supplementary angles)
170°+ ∠DPB =180°
∠DPB =180° - 170° = 10°
So, the measure of ∠DPB is 10°.
