7 1/2 lb =_oz<br> please help me

The revenue of a company is represented by r(x) and the expenses of the company are represented by e(x). What would you do to fi

Nesterboy [21]

We are given with the function of r (x) that represents the revenue or the total sales of the company and e(x) which represents the expenses of the company. Profit, p(x), is expressed as the difference between the revenue and the sales. The answer to this problem is B.

5 0

3 years ago

Read 2 more answers

A researcher claims that the mean of the salaries of elementary school teachers is greater than the mean of the salaries of seco

Brut [27]

Answer:

$t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921$

$df=n_{A}+n_{B}-2=26+24-2=48$

Since is a one sided test the p value would be:

$p_v =P(t_{(48)}>1.921)=0.0303$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X_{A}=48250$ represent the mean of elementary teachers

$\bar X_{B}=45630$ represent the mean for secondary teachers

$s_{A}=3900$ represent the sample standard deviation for elementary teacher

$s_{B}=5530$ represent the sample standard deviation for secondary teachers

$n_{A}=26$ sample size selected

$n_{B}=24$ sample size selected

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean of the salaries of elementary school teachers is greater than the mean of the salaries of secondary school teachers, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{B}\leq 0$

Alternative hypothesis: $\mu_{A}-\mu_{B}>0$

We don't know the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{B})}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{A}+n_{B}-2=26+24-2=48$

Since is a one sided test the p value would be:

$p_v =P(t_{(48)}>1.921)=0.0303$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

5 0

3 years ago

Create a pattern with the rule n-4

aalyn [17]

You would make a table first, the top part, just start from zero and add every time. Hope this helps

5 0

3 years ago

Please help me I’m struggling

zhannawk [14.2K]

Answer:

-2\3

Step-by-step explanation:

3 0

3 years ago

Omar is putting 5 liters of water in two goldfish bowls. He spills 200 milliliters of water and divides the remaining water even

DedPeter [7]

Answer:

a) 0.2 L

b) 4800 ml

c) 2400 ml

Step-by-step explanation:

Total volume of water = 5 litres

Since 1000 milliliters make 1 L

5L = 5000 ml

a) litres of water spilt = 200/1000 = 0.2 L

b) milliliters of water remaining = 5000 - 200 = 4800 ml

c) since it was expressly stated in the question that the remaining water was divided evenly; 4800/2 = 2400 ml in each bowl

4 0

3 years ago

7 1/2 lb =_oz please help me