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zhannawk [14.2K]
4 years ago
12

A rectangle's length is 6 units greater than its width. Write an equation expressing the rectangle's area, A, as a function of w

. A) A = 2w + 6 B) A = 4w + 12 C) A = w2 + 6w D) A = w2 + 12w
Mathematics
2 answers:
Dafna11 [192]4 years ago
6 0
I hope this helps you



length =width +6


Area=width × length



Area=w. (w+6)
maks197457 [2]4 years ago
3 0

Answer:

Option C is correct.

an equation expressing the rectangle's area , A = w^2+6w

Step-by-step explanation

Area of rectangle(A) is given by:

A = lw

where,

l is the length of the rectangle and w is the width of the rectangle.

As per the  statement:.

A rectangle's length is 6 units greater than its width

⇒l = 6+w

Substitute in the above formula;a we have;

A = (6+w) \cdot w

Using distributive property we have;

A = 6w+ w^2

or

A = w^2+6w

Therefore, an equation expressing the rectangle's area is, A = w^2+6w

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If dab = cba, d = 130 and c = 4x - 14 x = ?
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Answer:

38

Step-by-step explanation:

By CPCTC, angles C and D are congruent.

130 = 4x - 14

144 = 4x

x = 38

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What is the radius of a sphere whose surface area is 100 square centimeters?
professor190 [17]

Answer:

Step-by-step explanation:

The formula for determining the surface area of a sphere is expressed as

Surface area = 4πr^2

Where

r represents the radius of the sphere

π is a constant whose value is 3.14

From the information given,

Surface area of the sphere = 100 centimeters ^2. Therefore,

100 = 4 × 3.14 × r^2

100 = 12.65r^2

r^2 = 100/12.65 = 7.9051

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7 0
3 years ago
If 6x^4+8x^3-5x^2+ax+b is completely divisible by 2x^2-5 then find the value of a and b.
mixas84 [53]

Answer:

  • The value of a = -20
  • The value of b=-25

Step-by-step explanation:

Let

p(x)=6x^4+8x^3-5x^2+ax+b

and

q(x)=2x^2-5

As q(x) is exactly divisible, so, the remainder is 0.

∴ p(x)=q(x).g(x)+r(x)

6x^4 + 8x^3 - 5x^2 + ax + b = (\sqrt{2} x - \sqrt{5})(\sqrt{2} x + \sqrt{5}) g(x)

As the R.H.S becomes 0 when x = \sqrt{\frac{5}{2} } and x = -\sqrt{\frac{5}{2} }.

And

by substituting x = \sqrt{\frac{5}{2} }

6(\sqrt{\frac{5}{2} } )^4 + 8(\sqrt{\frac{5}{2} } )^3 - 5(\sqrt{\frac{5}{2} } )^2 + a(\sqrt{\frac{5}{2} } ) + b = 0

25 + 20( \frac{\sqrt{5}}{\sqrt{2}} ) + a( \frac{\sqrt{5}}{\sqrt{2}}) +b =0...[A]

by substituting x = -\sqrt{\frac{5}{2} }

25 - 20( \frac{\sqrt{5}}{\sqrt{2}} ) - a( \frac{\sqrt{5}}{\sqrt{2}}) +b =0.....[B]

Adding Equation [A] and equation [B]

50 +2b =0

b=-25

Subtracting Equation [A] and equation [B]

40(\sqrt{\frac{5}{2} } ) + 2a(\sqrt{\frac{5}{2} } ) =0

a = -20

Therefore,

  • The value of a = -20
  • The value of b=-25

<em>Keywords:</em><em> equation, solution</em>

<em> Learn more about equation solution from brainly.com/question/12687078</em>

<em> #learnwithBrainly</em>

3 0
3 years ago
I need help please with this question!!
Ira Lisetskai [31]
Sorry but where is the question
8 0
3 years ago
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