8.0 m/s if there is no air resistance. (B)
Less if there IS any air resistance.
Answer:
The radius of the loop is 20.66 km
Explanation:
let the radius of the loop be r
mass of airplane is m
At the top, the pilot experiences two radial forces, which are
1) Gravitational force is mg
2) Centrifugal forces mv²/r out of the center
When the pilot experiences no weight,
then, mg = mv²/r
r = v² / g
= 450² / 9.8
= 20.66 x 10³3
= 20.66 km
Answer:
Carbohydrate, Fat and Protein
Explanation:
⚠WARNING DO NOT JOIN THE ZOOM OF 825 338 1513⚠ OR DO NOT JOIN ANY ZOOMS FROM ANYONE EXCEPT REAL LIFE FRIENDS OR FRIENDS FAMILY OR TEACHERS! HIS ZOOM NAME IS Mysterious Men HE ASKS GIRLS TO DO INAPPROPRIATE THINGS PLS COPY AND PASTE THIS TO OTHER COMMENT SECTIONS! PLS PASS THIS AROUND
The velocity of the second glider after the collision is 4.33 m/s rightward.
<h3>
Velocity of the second glider after the collision</h3>
Apply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
- m₁ is mass of first glider
- m₂ is mass of second glider
- u₁ is initial velocity of first glider
- u₂ is initial velocity of second glider
- v is the final velocity of the gliders
(2)(1) + (3)(5) = (2)(2) + 3v₂
17 = 4 + 3v₂
3v₂ = 17 - 4
3v₂ = 13
v₂ = 13/3
v₂ = 4.33 m/s
Thus, the velocity of the second glider after the collision is 4.33 m/s rightward.
Learn more about linear momentum here: brainly.com/question/7538238
#SPJ1
