What can subatomic particles be broken down into?

What caused the light to shine on the paper above the mirror?

Shalnov [3]

Answer:

The Light was reflected, b.

Explanation:

If the flashlight was pointed at the mirror, it was reflected because it did not stop on the mirror or go through the mirror or reflect in different ways.

4 0

3 years ago

Liquid sodium can be used as a heat transfer fluid. Its vapor pressure is 40.0 torr at 633°C and 400.0 torr at 823°C. Calculate

kaheart [24]

Answer:

H vaporization = 100.0788 kJ/mol

Explanation:

Use clausius clapyron's adaptation for the calculation of Hvap as:

$ln\frac {P_2}{P_1}=\frac {H_{vap}}{R}(\frac {1}{T_1}-\frac {1}{T_2})$

Where,

P₂ and P₁ are the pressure at Temperature T₂ and T₁ respectively.

R is the gas constant.

T₂ = 823°C

T₁ = 633°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So, the temperature,

T₂ = (823 + 273.15) K = 1096.15 K

T₁ = (633 + 273.15) K = 906.15 K

P₂ = 400.0 torr , P₁ = 40.0 torr

R = 8.314 J/K.mol

Applying in the formula to calculate heat of vaporization as:

$ln \frac {400}{40}=\frac {H_{vap}}{R} (\frac {1}{906.15}-\frac {1}{1096.15})$

Solving for heat of vaporization, we get:

H vaporization = 100078.823 J/mol

Also, 1 J = 10⁻³ kJ

So,

<u>H vaporization = 100.0788 kJ/mol</u>

4 0

3 years ago

A sheet of gold leaf has a thickness of 0.125 micrometer. A gold atom has a radius of 174pm. Approximately how many layers of at

Olegator [25]

Answer:

719

Explanation:

Conversion

1 picometer (pm) is equivalent to $1 × 10^{-12}$ meter

1 micrometer is equivalent to $1 × 10^{-6}$ meter

To find the number of layers, we divide the overal leaf thickness by the thickness of one atom hence dividing tex]0.125 × 10^{-6}[/tex] meter by $174 × 10^{-12}$ meter we get that the number of sheets will be as follows

$\frac {0.125× 10^{-6}}{174\times 10^{-12}}=718.3908045\approx 719$

Therefore, they are approximately 719 sheets

7 0

3 years ago

A 0.45 kg soccer ball changes its velocity by 20.0 m/s due to a force applied to it in 0.10 seconds. What force was necessary fo

Sonja [21]

For this problem, we will need the famous equation F=ma, as detailed by Isaac Newton.

F=mass x acceleration, where Force is in Newtons.

20 m/s represents the quantity of speed change, but to use in the equation, we need acceleration, not speed. Acceleration is the velocity change over a unit time, so changing 20 m/s in 0.1 seconds means that the acceleration was 200 m/s^2.

Plugging in all your numbers, you find:

F=(0.45 kg)(200 m/s^2) = 90 N of force.

6 0

3 years ago

A weight lifter picks up a barbell and

kodGreya [7K]

Answer:

From highest to lowest: $W_1>W_2>W_3$

Explanation:

The work done by a force is given by

$W=Fd cos \theta$

where:

F is the force applied on the object

d is the displacement of the object

$\theta$ is the angle between the direction of the force and of the displacement

In case 1), the barbell is lifted upward. This means that:

- the force applied is upward

- the displacement of the object is upward

This means that $0$ , so the work done is positive: $W_1>0$

In case 2), the barbell is held stationary: this means that the displacement is zero,

$d=0$

And therefore, this means that the work done is also zero:

$W_2=0$

In case 3), the barbell is put down slowly, without dropping it. This means that:

- The force applied is still upward (in fact, the force applied must be upward in order to overcome the force of gravity downward, and avoid the barbell to fall down)

- The displacement of the barbell is downward

This means that $90^{\circ}$ , so $cos \theta$ , and therefore the work done is negative:

$W_3$

So the ranking from greatest to smallest work is

$W_1>W_2>W_3$

8 0

3 years ago