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Inessa05 [86]
3 years ago
8

What can subatomic particles be broken down into?

Physics
1 answer:
AfilCa [17]3 years ago
5 0
Subatomic particles cannot be broken down any further
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Answer these questions about a light year.?
aliina [53]

These are five questions and five answers:

a. State the speed in m/sec using scientific notation

i) Find the place value of the digit with the highest place value (the digit most to the left) in the number 300,000,000: hundred millions.

ii) Determine the number of zeros corresponding to that place value: 9

ii) Write the digit with the highest place value, mulitplied by the power of ten with exponent equal to the number of zeros corresponding to the place of such digit less 1 (9 - 1 = 8): 3 × 10⁸

iii) Complete with the units: 3 × 10⁸ m/s ← answer

b. State the speed in km/sec using scientific notation

i) State the conversion factor: 1 km = 1000 m = 10³ m

⇒ 1 = 1 km / 10³ m

ii) Multiply by the conversion factor:

3 × 10⁸ m/s × 1 km / (10³ m)

iii) Simplify (cancel the units that are common in the numerator and denominator)

3 × (10⁸ / 10³) km/s = 3 × 10⁵ km/s ← answer

c. State the number of seconds in one year using scientific notation

i) Find the place value of the digit with the highest place value (the digit most to the left) in the number 32,000,000: ten millions.

ii) Determine the number of zeros corresponding to that place value: 8

ii) Write the digit with the highest place value, as integer, add the other significant figures as decimals, mulitplied by the power of ten with exponent equal to the number of zeros corresponding to the place of the digit with highest place value less 1 (8 - 1 = 7): 3.2 × 10⁷

iii) Complete with the units: 3.2 × 10⁷ s ← answer

d. Calculate the distance in meters of one light year

i) distance formula: distance = speed × time

ii) Replace with the numbers in scientific notation:

distance = 3 × 10⁸ m/s × 3.2 × 10⁷ s

iii) Simplify (due the operations and cancel the units that are common in the numerator and denominator)

3 × 10⁸ m/s × 3.2 × 10⁷ s = 9.6 × 10 ¹⁵ m ← answer

e. State this distance in centimeters

i) State the conversion factor: 1m = 100 cm = 10² cm

⇒ 1 = 10² cm / 1 m

ii) Multiply by the conversion factor: 9.6 × 10 ¹⁵ m × 10² cm / 1 m

iii) Simplily: 9.6 × 10⁷ cm ← answer


4 0
3 years ago
Read 2 more answers
Martije has made a slight error in naming a compound monocarbon tetrabromide. What compound is she most likely naming, and what
Alik [6]

Answer: CBr_4 : carbon tetrabromide

Explanation:

CBr_4 is a covalent compound because in this compound the sharing of electrons takes place between carbon and bromine. Both the elements are non-metals. Hence, it will form covalent bond.

The naming of covalent compound is given by:

1. The less electronegative element is written first.

2. The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.

3. If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.

Hence, the correct name for CBr_4 is carbon tetrabromide.

7 0
3 years ago
Read 2 more answers
When the current in a toroidal solenoid is changing at a rate of 0.0260 A/s, the magnitude of the induced emf is 12.6 mV. When t
andrew11 [14]

Answer:

N= 238 turns

Explanation:

The induced Emf that goes through a solenoid can be calculated using the below formula;

Where ξ=induced Emf

L= self inductance

I= current

ξ= L|dⁱ/dt|

Making L which is the self inductance subject of formula we have

L=ξ/[|dⁱ|*|dt|]

The current here is changing at the rate of

.0260 A/s

L=NΦB/i

N=ξ/Φ|di|*|dt|

Magnitude of the induced Emf given= 12.6mV then if we convert to volt we have 12.6×10⁻³ V

The current I = 1.40A

Magnitude flux through the flux=/0.00285 Wb

Then if we substitute all this Value to equation above we have

N=(12.6×10⁻³ V×1.40A)/(0.00285 Wb×0.0260 A/s)

N=238turn

Therefore, there are 238turns in the solenoid

4 0
3 years ago
Which best explains why the diagram shows refraction but not reflection?
Aleonysh [2.5K]

It shows the ray passing through the boundary.

8 0
3 years ago
Read 2 more answers
A 0.40 kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.0 m on a frictionless horizontal su
DerKrebs [107]
<span>The centripetal force for such an arrangement can be found through the equation Fc = mv^2/r where m is the mass of the rotating object, v is that object's velocity, and r is the radius of rotation. In this case, we know that the maximum Fc that can be tolerated by the cord is 64N. Thus we set the equation up and solve for the value of v for which Fc = 64.
   64 = 0.4*(v^2)/1
 64/0.4 = 160 =
v^2 v = sqrt(160) = 12.65 m/s

   At any speed faster than 12.65 m/s, the cord will break.</span>
3 0
3 years ago
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