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german
2 years ago
9

When a guitar string is plucked, the guitar string oscillates as a result of waves moving through the string. The vibrations of

the string cause the air molecules to oscillate, forming sound waves. The frequency of the sound waves is equal to the frequency of the vibrating string. Is the wavelength of the sound wave always equal to the wavelength of the waves on the string
Physics
1 answer:
oksian1 [2.3K]2 years ago
4 0

Answer:

Explanation:

Wave produced in string and waves produced in air are different . The only similarity is that their frequency are equal . Otherwise , no similarity . One is transverse ( on wire ) , the other is longitudinal ( air ) . Their velocities too are different .

velocity = wavelength x frequency

if frequency is constant

wavelength  ∝  velocity

wavelength is proportional to velocity . Since their velocities are different , their wavelength too will be different.

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Answer:

 F = 1.047 10⁻² N

Explanation:

Let's use kinematics to find the angular acceleration

             w = w₀ + α t

as for rest w₀ = 0

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             α = w / t

let's reduce the magnitudes to the SI system

              w = 1000 rev / min (2π rad/ 1 rev) (1 min/ 60s) = 104.72 rad / s

              m = 1.00 g (1 kg / 1000 g) = 1,000 10⁻³ kg

              r = 10.0 cm (1 m / 100 cm) = 0.100 m

let's calculate

              α = 104.72 / 1

              α = 104.72 rad / s²

angular and linear variables are related

               a = α  r

               a = 104.72 0.100

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finally we substitute in Newton's second law

               F = 1 10⁻³ 10.47

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