Surface Area of a Sphere is...

Now...

The answer is Option C
Answer:
The work done in stretching the spring is 8 lb.ft
Step-by-step explanation:
Given;
Applied force, F = 192 lb
extension of the spring, x = 3 ft
Determine the spring constant from the applied force and extension;

When the spring is stretched 6 inches beyond its natural length, the work done is calculated as follows;
x = 6 inches = 0.5 ft

Therefore, the work done in stretching the spring is 8 lb.ft

I used the Pythagorean formula, which is a² + b² = c².
a² and b² are the two side legs while c² is the hypotenuse.
One of the side is 42 - 8 = 34 cm.
Answer:
The answer is -7.15, hope this helps.
Answer:
a Destiny
b depending on liquid they would be less dense