Question

Pls answer my question from the above picture

Answer 1

Step-by-step explanation:

I HOPE THIS THIS HELPS U.

Answer 2

Answer:

Step-by-step explanation:

$a^{m}* a^{n}=a^{m+n}\\\\\\(\frac{-1}{2})^{-19}*(\frac{-1}{2})^{8}=(\frac{-1}{2})^{-2x +1}\\\\(\frac{-1}{2})^{-19+8}=(\frac{-1}{2})^{-2x+1}\\\\\\(\frac{-1}{2})^{-11}=(\frac{-1}{2})^{-2x+1}$

As bases are equal in boht sides, we can compare the exponents.

-2x + 1 = -11

Subtract 1 form both sides

-2x = -11 - 1

-2x = -12

Divide both sides by -2

x = -12/-2

x = 6