Reaction involved in present electrochemical cell,
At Anode: Zn → Zn^2+ + 2e^2-
At cathode: Zn^2+ + 2e^2- → Zn
Net Reaction: Zn + Zn^2+ ('x' m) → Zn^2+(0.1 m) + Zn
Number of electrons involved in present electrochemical cell = n = 2
According to Nernst equation for electrochemical cell,
Ecell = -2.303
= 0.014
Given: T =
, F = 96500 C, R = gas constant = 8.314J/K.mol, [Zn^2+]R = 0.1 m , Ecell = 0.014 v
∴ 0.014 = - 2.303
∴ log
=
= -2.1117
∴ log x = log(0.1) + 2.1117
∴x = 13.09 m
The answer to this question is yes i think
Answer:
The correct answer is A
Explanation:
Hydrogen, oxygen, chlorine are the most abundant elements in oceans.
Oxygen is 85.84% by mass
Hydrogen is 10.82% by mass
Chlorine is 1.94% by mass
Answer:
The answer to your question is: below
Explanation:
Reaction with water, sodium is very reactive, sometimes explosive with water, so we can identified it from the other metals. Magnesium is less reactive than sodium, but in the presence of water it can produce bubbles.
Then we can identify copper and stainless steel because of the shine and they conduct electricity (conductivity).