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3 years ago

How many grams of CaCl, are needed to prepare 120 mL of 450 M Cach solution?

Chemistry

1 answer:

harkovskaia [24]3 years ago

5 0

Answer:

<em>gggyyhhhhjjjjjjhhhhhhhhhhhhhjjjjj</em>

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Calculate a reasonable amount (mass in g) of your unknown acid to use for a titration. You will want about 30 mL of titrant to g

Vinil7 [7]

Answer:

"0.60 g" is the appropriate solution.

Explanation:

The given values are:

Volume of base,

= 30 ml

Molarity of base,

= 0.05 m

Molar mass of acid,

= 400 g/mol

As we know,

⇒ $Molarity=\frac{Number \ of \ moles \ of \ base}{Number \ of \ solution}$

On substituting the values, we get

⇒ $0.05=\frac{Number \ of \ moles \ of \ base}{30\times 10^{-3}}$

⇒ $Number \ of \ moles \ of \ base=0.05\times 30\times 10^{-3}$

⇒ $=1.5\times 10^{-3}$

hence,

⇒ $Moles \ of \ acid=\frac{Mass \ of \ acid}{Molar \ mass \ of \ acid}$

On substituting the values, we get

⇒ $1.5\times 10^{-3}=\frac{Mass \ of \ acid}{400}$

⇒ $Mass \ of \ acid=1.5\times 10^{-3}\times 400$

⇒ $=0.60 \ g$

8 0

3 years ago

How many control(s) are in an experiment

weqwewe [10]

You can have as many controls as necessary, But they must remain equal at all times in order to get the most accurate results

6 0

3 years ago

Is weathering long term or short term and why

Marrrta [24]

Long term because if you leave something out to be weathered then it can’t be unweathered because of the drastic change of the object.

4 0

3 years ago

Consider the reaction: P(s) + 5/2 Cl2(g)PCl5(g) Write the equilibrium constant for this reaction in terms of the equilibrium con

Pani-rosa [81]

Answer: The equilibrium constant for the overall reaction is $K_a\times K_b$

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios.

a) $P(s)+\frac{3}{2}Cl_2(g)\rightarrow PCl_3(g)$

$K_a=\frac{[PCl_3]}{[Cl_2]^{\frac{3}{2}}}$

b) $PCl_3(g)+Cl_2(g)\rightarrow PCl_5(g)$

$K_b=\frac{[PCl_5]}{[Cl_2]\times [PCl_3]}$

For overall reaction on adding a and b we get c

c) $P(s)+\frac{5}{2}Cl_2(g)\rightarrow PCl_5(g)$

$K_c=\frac{[PCl_5]}{[Cl_2]^\frac{5}{2}}$

$K_c=K_a\times K_b=\frac{[PCl_3]}{[Cl_2]^{\frac{3}{2}}}\times \frac{[PCl_5]}{[Cl_2]\times [PCl_3]}$

The equilibrium constant for the overall reaction is $K_a\times K_b$

4 0

3 years ago

How much heat is required to change the temperature of 100 grams of water from 25 to 55oc?

marysya [2.9K]

Hthe heat required to change the temperfature of 100 grams of water from 25 to 55 c is calculated as below

Q(heat) = M(mass) x C(specific heat capacity) x delta T(change in temperature)

M= 100 grams
C= 4.18 j/g/c
delta T= 55-25 =30c

Q=100 g x4.814 j/g/c x 30c = 12552 joules

5 0

3 years ago