All categories

2 years ago

Option 1: Individual Activity

1 answer:

5 0

The country located at coordinates N 35°00' 00", latitude and E 33°00' 00" longitude is Cyprus and is surrounded by the Mediterranean Sea. The country I would like to go to would be the one located at coordinates N 41°89'01" E 12°49'22".

<h3>What is a geographic coordinate?</h3>

Geographic coordinates is a term that refers to a reference system that has the objective of identifying a point located on Earth using a system of numbers, letters or symbols.

The geographical coordinates take as reference points the Greenwich meridian (longitude 0°) and the line of the equator (latitude 0°). On the other hand, longitudes range from 0° to -180° or 180° and latitudes range from 0° to 90° or -90°.

According to the above, it can be inferred that the location of the coordinates N 35°00' 00", latitude and E 33°00' 00" longitude is the country of Cyprus surrounded by the Mediterranean Sea.

Learn more about geographic coordinates in: brainly.com/question/10760270

You might be interested in

Which of the following is the correctly balanced equation for the reaction of a Ca(OH)2 and HNO3

lakkis [162]

Your answer is
Ca(OH)₂ + 2HNO₃ → Ca(NO₃)₂ + 2H₂O I hope it is at least :P

4 0

3 years ago

What is the electron configuration for iodine

iogann1982 [59]

Hello!

To find electron configuration for Idoine we need to understand the following steps:

Finding the Atom's Atomic Number (tells us the specific number of electrons)
Determining the Charge of the Atom
Understanding the orbitals (Set S [Contains 2], P [Contains 3, Holds 6], D [Contains 5, Holds 10], F [Contains 7, Holds 14], and there are some theoritical ones.) [Overall the sets go SPDFGHIK
Understanding notations in configuartion. The notations display the number of electrons in the atom and set.

In this case, for Iodine. If we follow these rules we can see that the electron configuration is [Kr] 4d^10 5s^2 5p^5. We use Krytpon in front because that is the last full and stable noble gas before this particular element. Atoms are just trying to be stable so the goal is to achieve that full shell.

7 0

3 years ago

Which of the following rules should you follow to balance chemical equations?

Firdavs [7]

Answer:

c. add coefficients as needed

Explanation:

A chemical equation is defined as the equation that shows changes in a chemical reaction. A chemical equation consist of reactant and product, reactant is at left side of the arrow and product is at right side of the arrow.

Reactant => Product

While balancing a chemical equation, the basic rule is to balance the coefficient as required. Coefficient represents the number of molecules and is used at front of a chemical symbol. Change in coefficient helps balance the number of atoms or molecules of the substances on both the sides of the arrow.

Subscripts are never allowed to change because it can change the chemical involved in the reaction.

Hence, the correct answer is "c. add coefficients as needed".

3 0

3 years ago

SCIENCE QUEASTION I PUTED IT IN CHEMISTRY BECAUSE BRAINLY HAS NO SCIENCE WILL MARK BRAINLIEST

Elena L [17]

#1. The condition of the atmosphere at a certain time and certain place

#2. The rate of evaporation is EQUAL to the rate of condensation

Please mark Brainliest if this was helpful! :)

7 0

3 years ago

Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 Pb(ClO3)2 with aqueous NaI . NaI. Include phases. chemica

FinnZ [79.3K]

<u>Answer:</u> The mass of precipitate (lead (II) iodide) that will form is 119.89 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI solution = 0.130 M

Volume of solution = 0.400 L

Putting values in above equation, we get:

$0.130M=\frac{\text{Moles of NaI}}{0.400L}\\\\\text{Moles of NaI}=(0.130mol/L\times 0.400L)=0.52mol$

The balanced chemical equation for the reaction of lead chlorate and sodium iodide follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

The precipitate (insoluble salt) formed is lead (II) iodide

By Stoichiometry of the reaction:

2 moles of NaI produces 1 mole of lead (II) iodide

So, 0.52 moles of NaI will produce = $\frac{1}{2}\times 0.52=0.26mol$ of lead (II) iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of lead (II) iodide = 0.26 moles

Molar mass of lead (II) iodide = 461.1 g/mol

Putting values in above equation, we get:

$0.26mol=\frac{\text{Mass of lead (II) iodide}}{461.1g/mol}\\\\\text{Mass of lead (II) iodide}=(0.26mol\times 461.1g/mol)=119.89g$

Hence, the mass of precipitate (lead (II) iodide) that will form is 119.89 grams

4 0

3 years ago