Question

fourth,sixth and thirteenth term in this sequence A(n)= 6+(n+1)(-2) help me to find and describe the explicite formula

Answer 1

Hello,

A(n)=6+(n+1)^(-2)=6+1/(n+1)²

$A_{4} =6+ \dfrac{1}{(4+1)^2} =6+ \dfrac{1}{25}= \dfrac{151}{25} \\ A_{6} =6+ \dfrac{1}{(6+1)^2} =6+ \dfrac{1}{49}= \dfrac{295}{49} \\ A_{13} =6+ \dfrac{1}{(13+1)^2} =6+ \dfrac{1}{196}= \dfrac{1177}{196}$