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s344n2d4d5 [400]

3 years ago

11

I need big help!!! The cost of a school banquet is $25 plus $15 for each person attending. Create a table, sketch the graph, and

write an equation in slope-intercept and point-slope form that gives total cost as a function of the number of people attending. What is the cost for 77 people?

1 answer:

Zepler [3.9K]3 years ago

6 0

Y= 15x + 25 - slope intercept
y-25=15x - point-slope
$1,180 - cost for 77 people

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Which value of n makes the equation true?<br><br> 2/3n = -12

vivado [14]

Answer:

-1/18

Step-by-step explanation:

Let's multiply left and right by 3n:

2 = -12 * 3n =>

-36n = 2

now divide by -36:

n = 2/-36 = -1/18

5 0

2 years ago

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Part III: Bailey works part-time at a movie theater. The theater pays employees an hourly wage based on their length of employme

frutty [35]

Given the following table showing the hourly wages of employees of a movie theater based on their length of employment.

<span>Length of employment (months)         Hourly wage (dollars/hour)
6 months    7.55
12 months    7.85
18 months    8.15
24 months    8.45

To obtain an algebraic expression </span>that describes how much Bailey’s employer pays part-time workers, we take two points from the table.

Recall that the equation of a linear function satisfying two points
$(x_1,y_1)$ and $(x_2,y_2)$
is given by
$\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}$

Given the two points (6, 7.55) and (12, 7.85), the algebraic expression relating the two points is given by
$\frac{y-7.55}{x-6} = \frac{7.85-7.55}{12-6} = \frac{0.3}{6} \\ \\ 6(y-7.55)=0.3(x-6) \\ \\ 6y-45.3=0.3x-1.8 \\ \\ 0.3x-6y=-43.5$

Therefore, the <span>algebraic expression that describes how much Bailey’s employer pays part-time workers is
$0.3x-6y=-43.5$ </span>

5 0

2 years ago

La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?

malfutka [58]

Answer:

Falso.

Step-by-step explanation:

Sea $d = \frac{a}{b}$ un número racional, donde $a, b \in \mathbb{R}$ y $b \neq 0$ , su opuesto es un número real $c = -\left(\frac{a}{b} \right)$ . En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) <em>El exponente es cero.</em>

(b) <em>El exponente es un negativo impar.</em>

(c) <em>El exponente es un negativo par.</em>

(d) <em>El exponente es un positivo impar.</em>

(e) <em>El exponente es un positivo par.</em>

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, $c = d = 1$ . La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

$d' = d^{-n}$ y $c' = c^{-n}$

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

$d' = \left(\frac{a}{b} \right)^{-n}$ y $c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}$

$d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}$ y $c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}$

$d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}$ y $c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}$

$d' = \left(\frac{b}{a} \right)^{n}$ y $c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}$

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}$

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = \left[-\left(\frac{b}{a} \right)\right]^{n}$

Si $n$ es impar, entonces:

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = - \left(\frac{b}{a} \right)^{n}$

Puesto que $d' \neq c'$ , la proposición es falsa.

(c) El exponente es un negativo par.

Si $n$ es par, entonces:

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = \left(\frac{b}{a} \right)^{n}$

Puesto que $d' = c'$ , la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

$d' = d^{n}$ y $c' = c^{n}$

$d' = \left(\frac{a}{b}\right)^{n}$ y $c' = \left[-\left(\frac{a}{b} \right)\right]^{n}$

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}$

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}$

Si $n$ es impar, entonces:

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = - \left(\frac{a}{b} \right)^{n}$

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = \left(\frac{a}{b} \right)^{n}$

Si $n$ es par, entonces $d' = c'$ y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.

3 0

3 years ago

(x-yi)(3+5i) is the conjugate of 6+24i

Nataly_w [17]

Answer:

x=-3

y=3

(-3-3i)(3+5i)

Step-by-step explanation:

$(x-yi)(3+5i)\\=3x+5xi-3yi+5y\\=(3x+5y)+(5x-3y)i\\$

and we have that must equal

6-24i

3x+5y=6

5x-3y=-24 and if we work it we found out that the solutions are

x=-3 and

y=3

5 0

2 years ago

Can someone pls help!

stira [4]

Answer:

I'm not quite sure, but I think 3. v= 5 × 32 × 10

and the rest I'm not sure.

7 0

2 years ago

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