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Andreyy89
3 years ago
10

A pice of lumber 2 1/4 feet long is to be cut into 3 equal pieces. How long will each piece be? Give the measurements in feet an

d inches.​
Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0

Answer: The required length of each piece of wood is  or 9 inches.

Step-by-step explanation:  Given that a piece of lumber is  feet long is to be cut into 3 equal pieces.

We are to find the length of each piece of wood in feet and in inches.

We will be using the UNITARY method to solve the given problem.

The length of 3 pieces of wood is equal to  

Therefore, the length of each piece of wood will be

Thus, the required length of each piece of wood is  or 9 inches.

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3 years ago
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The following frequency table summarizes the number of children that dads in Dads Club have.
attashe74 [19]

Answer:

C

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The probability that the dad of Dads Club has fewer than 3 children is

Pr=\dfrac{10}{20}=0.5 \text{ or } 50\%.

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8 0
3 years ago
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2 years ago
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Please help! <br><br> If f (x) = 1/9 x-2 what is f^-1(x)
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Look at the picture<br>​
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\large\displaystyle\text{$\begin{gathered}\sf 9|x-8| < 36 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Divide \ both \ sides \ by \ 9. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf  \frac{9(|x-8|)}{9} < \frac{36}{9}   \end{gathered}$}
  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}

<u>                                                                                                                             </u>

         \large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}

<u>                                                                                                                             </u>

           \large\displaystyle\text{$\begin{gathered}\sf x-8 > -4 \ (Condition \ 2) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 > -4+8 \ (Add \ 8 \ to \ both \ \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x > 4 \end{gathered}$}

<u>                                                                                                                             </u>

<u />\underline{\boldsymbol{\sf{Answer}}}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf x < 12 \ and \ x > 4 \end{gathered}$} }

\large\displaystyle\text{$\begin{gathered}\sf Therefore,\bf{\underline{the \  correct \ option}} \  \end{gathered}$}\large\displaystyle\text{$\begin{gathered}\sf is \ \bf{\underline{"A"}}. \end{gathered}$}

6 0
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