Answer:
x=49
Step-by-step explanation:
you replace the unknown with a variable (x)
you subtract 7 three times, so it x-7-7-7=28 or x-21=28
you add 21 to both sides, then you get x=49
f(x)= -99.4x + 198.8
f(1) = -99.4*1 + 198.8 = 99.4
f(2) = -99.4*2 + 198.8 = 0
f(3) = -99.4*3 + 198.8 = -99.4
<span>f(4) = -99.4*4 + 198.8 = -198.8
</span>
Day 11
this is nothnig im just saying this cause it has to be 20 chharaters long
Answer:
Step-by-step explanation:
Left Hand Side
Change to sin(theta) and cos(theta)
csc(theta) = 1/sin(theta)
cot(theta) = cos(theta)/sin(theta)
1/sin(theta) - cos(theta)/sin(theta) Put over Sin(theta) Common denominator
[1 - cos(theta)] / sin(theta) Multiply numerator and denominator by 1 + cos(theta)
(1 - cos(theta)(1 + cos(theta) ) / sin(thata)*(1 + cos(theta))
(1 + cos(theta)(1 - cos(theta)) = 1 - cos^2(theta)
sin^2(theta) / (sin(theta)* ( 1 + cos(theta)
sin(theta) / (1 + cos(theta) )
Right hand Side.
See Above.
![\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-2}x^2\stackrel{\stackrel{b}{\downarrow }}{-8}x\stackrel{\stackrel{c}{\downarrow }}{+5} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{(-8)}{2(-2)}~~,~~5-\cfrac{(-8)^2}{4(-2)} \right)\implies \left( \cfrac{8}{-4}~~,~~5-\cfrac{64}{-8} \right)\implies (-2~~,~~5+8) \\\\\\ (-2~~,~~13)~\hfill \stackrel{\textit{axis of symmetry}}{x=-2}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvertex%20of%20a%20vertical%20parabola%2C%20using%20coefficients%7D%20%5C%5C%5C%5C%20y%3D%5Cstackrel%7B%5Cstackrel%7Ba%7D%7B%5Cdownarrow%20%7D%7D%7B-2%7Dx%5E2%5Cstackrel%7B%5Cstackrel%7Bb%7D%7B%5Cdownarrow%20%7D%7D%7B-8%7Dx%5Cstackrel%7B%5Cstackrel%7Bc%7D%7B%5Cdownarrow%20%7D%7D%7B%2B5%7D%20%5Cqquad%20%5Cqquad%20%5Cleft%28-%5Ccfrac%7B%20b%7D%7B2%20a%7D~~~~%20%2C~~~~%20c-%5Ccfrac%7B%20b%5E2%7D%7B4%20a%7D%5Cright%29%20%5C%5C%5C%5C%5C%5C%20%5Cleft%28%20-%5Ccfrac%7B%28-8%29%7D%7B2%28-2%29%7D~~%2C~~5-%5Ccfrac%7B%28-8%29%5E2%7D%7B4%28-2%29%7D%20%5Cright%29%5Cimplies%20%5Cleft%28%20%5Ccfrac%7B8%7D%7B-4%7D~~%2C~~5-%5Ccfrac%7B64%7D%7B-8%7D%20%5Cright%29%5Cimplies%20%28-2~~%2C~~5%2B8%29%20%5C%5C%5C%5C%5C%5C%20%28-2~~%2C~~13%29~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Baxis%20of%20symmetry%7D%7D%7Bx%3D-2%7D)
recall that the axis of symmetry for a vertical parabola is simply the equation for the vertical line of the vertex's x-coordinate.