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3 years ago

Please help!!!!!!!!!!!!

Chemistry

2 answers:

inessss [21]3 years ago

8 0

What is the question

Arisa [49]3 years ago

4 0

What’s the question?

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2. What was the primary reason in the 1850's driving the curiosity of atoms?

nalin [4]

The primary reason that large numbers of people left Ireland in the 1840s and 1850s was MASS STARVATION.

Great Famine or Great Hunger was a period in Ireland where mass starvation, diseases, and emigration occurred between 1845 to 1852.

The Great Famine was caused by Phytophthora infestans, a disease that infests in potatoes. Though the potato infestation spread throughout Europe, it greatly affected Ireland, where 1/3 of its population was dependent on the potato crop as their primary source of food.

The loss of their primary source of food led to mass starvation, sickness, and eventual death. Others opted to leave Ireland and seek shelter and food in other countries to survive.

4 0

3 years ago

23) A common reaction that occurs in cells is shown here. In the presence of oxygen, a glucose molecule is combusted to form car

maw [93]

Answer:

Explanation:

add them together and multiply by 2

5 0

2 years ago

The reaction below has an equilibrium constant kp=2.2×106 at 298 k. 2cof2(g)⇌co2(g)+cf4(g) calculate kp for the reaction below.

AnnZ [28]

I believe the correct 2nd reaction is:

cof2(g)⇌1/2 co2(g)+1/2 cf4(g)

where we can see that it is exactly one-half of the original

Therefore the new Kp is:

new Kp = (old Kp)^(1/2)

new Kp = (2.2 x 10^6)^(1/2)

new Kp = 1,483.24

8 0

3 years ago

Read 2 more answers

What happens when an electron jumps energy from energy level 3 energy level 6 in an atom

Alik [6]

Explanation:

high energy to Low energy

=the electron gains energy (K.E)

4 0

2 years ago

A synthesis reaction takes place when carbon monoxide (CO) and hydrogen gas (H2) react to form methanol (CH3OH). How many grams

jek_recluse [69]

The mass of methanol produced is 8.0 g.

We have the masses of two reactants, so this is a limiting reactant problem.

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.

Step 1. Gather all the information in one place with molar masses above the formulas and everything else below them.

MM: ___28.01 2.016 ___32.04

_______CO + 2H_2 → CH_3OH

Mass/g: 7.0 __2.5

Step 2. Calculate the moles of each reactant

Moles of CO = 7.0 g CO × (1 mol CO/28.01g CO) = 0.250 mol CO

Moles of H_2 =2.5 g H_2 × (1 mol H_2/2.016 g H_2) = 1.24 mol H_2

Step 3. Identify the limiting reactant

Calculate the moles of CH_3OH we can obtain from each reactant.

From CO: Moles of CH_3OH = 0.250 mol CO × (1 mol CH_3OH /1 mol CO)

= 0.250 mol CH_3OH

From H_2: Moles of CH_3OH = 1.24 mol H_2 × (1 mol CH_3OH /2 mol H_2)

= 0.620 mol CH_3OH

CO is the limiting reactant because it gives the smaller amount of CH_3OH.

Step 4. Calculate the mass of CH_3OH

Mass of CH_3OH = 0.250 mol CH_3OH × (32.04 g CH_3OH /1 mol CH_3OH) = 8.0 g CH_3OH

3 0

3 years ago