All categories

2 years ago

How does the plasma membrane contribute to the structure and function of the cell?

Chemistry

2 answers:

Gennadij [26K]2 years ago

7 0

Answer: It forms a rigid structure that only allows materials to exit the cell.

Explanation:

The primary function of the plasma membrane is to protect the cell from its surroundings. Composed of a phospholipid bilayer with embedded proteins, the plasma membrane is selectively permeable to ions and organic molecules and regulates the movement of substances in and out of cells.

An image of plasma membrane shows the phospholipid bilayer, embedded proteins, and cholesterol molecules. The plasma membrane is the border between the interior and exterior of a cell. As such, it controls passage of various molecules—including sugars, amino acids, ions, and water—into and out of the cell.

I hope this helped you have a good day.

Flauer [41]2 years ago

6 0

Answer: It forms a rigid structure around the cell that provides support to the cell

The primary function of the plasma membrane is to protect the cell from its surroundings. Composed of a phospholipid bilayer with embedded proteins, the plasma membrane is selectively permeable to ions and organic molecules and regulates the movement of substances in and out of cells.

An image of plasma membrane shows the phospholipid bilayer, embedded proteins, and cholesterol molecules. ... The plasma membrane is the border between the interior and exterior of a cell. As such, it controls passage of various molecules—including sugars, amino acids, ions, and water—into and out of the cell.

You might be interested in

What mass of methane (CH4) gas occupies a volume of 0,462 L at 1atm and 273K

LiRa [457]

Explanation:

Since methane gas is at 1 atm and 273 K, it is at standard temperature and pressure(STP).

One mole of every gas occupies 22.4 dm^3 at STP, and vice versa. So,

22.4 dm^3 at STP of CH4=1 mol=12+4(1)=16 g

0.462 L(0.462 dm^3) at STP of CH4

=(16 g×0.462 dm^3)/22.4 dm^3

=0.33 g

6 0

3 years ago

Find the initial concentration of the weak acid or base in each of the following aqueous solutions: (a) a solution of HClO with

Luda [366]

Answer:

a) 0.021 M

b) 0.019 M

Explanation:

To do this, you need to calculate the concentration of ions in solution with the given value of pH for each solution, then, write the chemical equation for both solutions, Set an ICE chart, use the value of Ka and Kb reported for both solutions, and solve for the initial concentration.

This is the general procedure to do it, now let's do it by parts.

a) Concentration of HClO pH = 4.6

With the given pH, we use the following expression:

pH = -log[H₃O⁺] From here, we solve for [H₃O⁺]

[H₃O⁺] = 10^(-pH) (1)

Let's calculate first the hydronium concentration:

[H₃O⁺] = 10^(-4.6) = 2.51x10⁻⁵ M

This value indicates the equilibrium concentration of this ion in solution. Now, to know the initial concentration of the acid, we need to do an ICE chart and write the chemical equation. This is an acid - base reaction, so we need the value of Ka of the acid.

HClO + H₂O <---------> H₃O⁺ + ClO⁻ Ka = 3x10⁻⁸

I: Y 0 0

C: -x +x +x

E: Y - x x x

With this chart, we need to write the expression for Ka which is:

Ka = [H₃O⁺] * [ClO⁻] / [HClO] = x² / Y-x

But we already know the concentration of [H₃O⁺], which is the same for [ClO⁻], and the value of Ka, so all we have to do is replace the values in the above expression and solve for Y:

3x10⁻⁸ = (2.51x10⁻⁵)² / Y - 2.51x10⁻⁵

We can round to Y because "x" is a very small value as it's value of Ka so:

3x10⁻⁸ = (2.51x10⁻⁵)²/Y

Y = (2.51x10⁻⁵)²/3x10⁻⁸

And this is the initial concentration of the acid.

b) Solution of hidrazine pH = 10.2

We do the same procedure as part a) with the difference that instead of using Ka , we use Kb and concentration of [OH⁻]. The Kb for hydrazine is 1.3x10⁻⁶

Let's calculate the [OH⁻]:

pOH = 14 - pH

pOH = 14 - 10.2 = 3.8

[OH⁻] = 10^(-3.8) = 1.58x10⁻⁴ M

The chemical equation:

N₂H₄ + H₂O <---------> N₂H₅⁺ + OH⁻ Kb = 1.3x10⁻⁶

I: Y 0 0

C: -x +x +x

E: Y-x x x

Kb = x²/(Y-x)

1.3x10⁻⁶ = (1.58x10⁻⁴)²/Y

Y = (1.58x10⁻⁴)²/1.3x10⁻⁶

And this is the initial concentration of hydrazine

4 0

3 years ago

According to le châtelier’s principle, the amount of solid reactant or product present does not have an impact on the equilibriu

Inessa05 [86]

The concentration of solids is constant and usually taken equal to unity ,therefore it does not appear in the equilibrium constant ,so adding or removing solid has no effect. So According to Le Chatelet's Principle the amount of solid reactant or product present does not have an impact on the equilibrium

What is Le Chatelet's Principle ?

The position of the equilibrium in a chemical reaction can be predicted with the aid of Le Chatelet's Principle in response to changes in temperature, concentration, or pressure. This is crucial, especially for industrial applications where it's crucial to predict and maximize yields.

According to Le Châtelet's principle, if a dynamic equilibrium is upset by changing the conditions, the equilibrium position will move to compensate for the change and restore the equilibrium.

To know about Le Chatelet's Principle from the link

brainly.com/question/2943338

#SPJ4

5 0

10 months ago

Fill in the blanks am giving brainliest and thanx

QveST [7]

Answer:

Organelles, prokaryotic, organelles, cytoplasm, prokaryotic, nucleus

Explanation:

Organelles are membrane bound only in eukaryotic ccells.

Prokaryotic cells unlike eukaryotic cells, do not have membrane bound organlles.

Something that is found in both prokaryotic and eukaryotic cells is the cytoplasm, which is fluid that is inside the whole cell.

Unlike eukaryotic cells, prokaryotic cells have loose DNA, which floats around the cell quite literally.

The only way DNA is stored in eukaroyotic cells is in the nucelus, which is only found in eukaryotic cells, not prokaryotic.

Hope this helps ;)

7 0

3 years ago

Please help me with question 8

omeli [17]

I think it might be B

8 0

3 years ago