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3 years ago

3 divided by 3 over 4

Mathematics

1 answer:

Delvig [45]3 years ago

4 0

3 / 3/4 is the same as 3 x 4/3 which is 12/3 which equals 4

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Marni danced in a contest to raise money for an animal shelter. Marni raised $30 plus $1.80 per minute that she danced. She rais

klio [65]

Total raised: 264

She raised 30 plus 1.80x (x being the number of minutes).

Equation: 264=1.8x+30

To solve for x, you need to isolate x. First, subtract 30 from both sides.

234=1.8x

Now, divide both sides by 1.8.

130=x

Marni danced 130 minutes.

I hope this helps :)

8 0

3 years ago

Read 2 more answers

Manuel ate 1/3 of the crackers on the plate. his brother ate 1/4 of the crackers. there were 5 crackers left.how many crackers w

Sedaia [141]

There were 11 crackers to begin with. Because if you give the fractions a common denominator of 12 you multiply how you got to 12 by the top as well then you would subtract and add it to the five that were left

8 0

3 years ago

Choose the correct simplification of the expression (7ab3)2.

Brums [2.3K]

You can use this equation to help you: (ab)^2 = a^2 b^2. And also (a^m)^n = a^m*n

So, here it is:

(7ab^3)^2 = 7^2 a^2 b^3*2 = 49a^2b^6

The correct answer is the third one - 49 a^2 b^6.

7 0

3 years ago

Read 2 more answers

Find the volume of a pyramid with a square base, where the side length of the base is

valina [46]

Answer:

Volume = 1114.1 $in^3$

Step-by-step explanation:

Recall that the formula for the volume of a pyramid is given by:

$Volume=\frac{1}{3} \,B\,*\,H$

where B is the area of the pyramid's base (in our case a square of side 12,8 in), and H the pyramid's height (in our case 20.4 in).

Then the square base of the pyramid has an area given by: $(12.8\,\,in)^2=163.84\,\,in^2$

Finally,we can now write the volume of the pyramid as:

$Volume=\frac{1}{3} \,B\,*\,H\\Volume=\frac{1}{3} \,(163.84)\,*\,20.4\,\,in^3\\Volume=1114.112\,\,in^3$

Rounding the answer to a tenth of a cubic inch, we get:

Volume = 1114.1 $in^3$

7 0

3 years ago

Eliminate the parameter t to find a cartesian equation for x=t^2 y=2+10t

postnew [5]

Hello :
$\left \{ {{x= t^{2} }...(1) \atop {y=2+ 10t }...(2)} \right.$
by(1) :
$t = \frac{y-2}{10}$
subsct in (2) :
$x = ( \frac{y-2}{10} )^{2}$ ....(<span>cartesian equation )</span>

3 0

3 years ago