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Ad libitum [116K]
3 years ago
15

A man is cleaning the roof of his house. He figures that his 15ft ladder will be stable if it leans on the house at a 55 angle h

ow far should the ladder base be from the house
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0

Answer:

the answer i think is 3.6

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Solve the system using elimination.<br><br> 5x + 8y = –29<br> 7x – 2y = –67
Snowcat [4.5K]
7x-2y+-67
<span>multiply both sides of the bottom by 4 and add </span><span>                                           5x+8y=-29 </span>
<span> 28x-8y=268</span>
 
  33x=-297
<span>   x=-9 </span>


<span>5(-9) +8y= -29 </span>
<span>-45 +8y =-29 </span>
<span>8y= 16 </span>
y=2
8 0
3 years ago
Find the volume of the solid generated when R​ (shaded region) is revolved about the given line. x=6−3sec y​, x=6​, y= π 3​, and
Dmitrij [34]

Answer:

V=9\pi\sqrt{3}

Step-by-step explanation:

In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).

The formula we will use for this problem is the following:

V=\int\limits^b_a {\pi r^{2}} \, dy

where:

r=6-(6-3 sec(y))

r=3 sec(y)

a=0

b=\frac{\pi}{3}

so the volume becomes:

V=\int\limits^\frac{\pi}{3}_0 {\pi (3 sec(y))^{2}} \, dy

This can be simplified to:

V=\int\limits^\frac{\pi}{3}_0 {9\pi sec^{2}(y)} \, dy

and the integral can be rewritten like this:

V=9\pi\int\limits^\frac{\pi}{3}_0 {sec^{2}(y)} \, dy

which is a standard integral so we solve it to:

V=9\pi[tan y]\limits^\frac{\pi}{3}_0

so we get:

V=9\pi[tan \frac{\pi}{3} - tan 0]

which yields:

V=9\pi\sqrt{3}]

6 0
3 years ago
How do you solve this equation: -2m+3=|15+m|
Elden [556K]

Any number inside the modulus sign becomes positive. This means |15+m|=|-(15+m)|=|-15-m| and so we have,

-2m+3=|15+m| \Rightarrow \left \Big\{ {{-2m+3=15+m} \atop{-2m+3=-15-m}} \right

Solving these gives us

-2m+3=15+m \Rightarrow m=-4

-2m+3=-15-m \Rightarrow = m=18

However if we check the second solution in the original equation we obtain -2(18)+3=|15+18| \Rightarrow -33=33. This is false and so m=18 can't be a solution.

Therefore the only solution is m=-4.

(Note: I'm not sure why the second solution didn't work but when there's a modulus sign involved it always pays to check your final answers to be sure. I'll have a think about it but in case you find out before I do, I'd be interested to know in the comments.)

8 0
3 years ago
Can you solve this step by step please
cluponka [151]

Answer:

(6.8  + 3.4) \times  {10}^{6}  \\  \\ 10.2 \times  {10}^{6}  \\  \\ 1.02 \times  {10}^{7}

I hope I helped you^_^

8 0
3 years ago
Find the slope of the line.<br><br> A.) 3/2<br> B.) - 2/3<br> C.) - 3/4<br> D.) 4/3
Julli [10]
Option C is your answer. 

It's a negative sloping line which eliminates A and D. Then you just do the whole rise-over-run deal to get the 3/4 part. 
8 0
3 years ago
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