7x-2y+-67
<span>multiply both sides of the bottom by 4 and add </span><span> 5x+8y=-29 </span>
<span> 28x-8y=268</span>
33x=-297
<span> x=-9 </span>
<span>5(-9) +8y= -29 </span>
<span>-45 +8y =-29 </span>
<span>8y= 16 </span>
y=2
Answer:

Step-by-step explanation:
In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).
The formula we will use for this problem is the following:

where:


a=0

so the volume becomes:

This can be simplified to:

and the integral can be rewritten like this:

which is a standard integral so we solve it to:
![V=9\pi[tan y]\limits^\frac{\pi}{3}_0](https://tex.z-dn.net/?f=V%3D9%5Cpi%5Btan%20y%5D%5Climits%5E%5Cfrac%7B%5Cpi%7D%7B3%7D_0)
so we get:
![V=9\pi[tan \frac{\pi}{3} - tan 0]](https://tex.z-dn.net/?f=V%3D9%5Cpi%5Btan%20%5Cfrac%7B%5Cpi%7D%7B3%7D%20-%20tan%200%5D)
which yields:
]
Any number inside the modulus sign becomes positive. This means
and so we have,

Solving these gives us


However if we check the second solution in the original equation we obtain
. This is false and so
can't be a solution.
Therefore the only solution is
.
(Note: I'm not sure why the second solution didn't work but when there's a modulus sign involved it always pays to check your final answers to be sure. I'll have a think about it but in case you find out before I do, I'd be interested to know in the comments.)
Option C is your answer.
It's a negative sloping line which eliminates A and D. Then you just do the whole rise-over-run deal to get the 3/4 part.