We can subtract the terms, because they both involve the variable $b$ , and we have $3b-7b = (3-7)b = -4b$
We can sum the terms, because they all involve the variable $a$ , and we have $a+a-5a = (1+1-5)a = -3a$
We can't sum this terms: 3 is a pure number, while 3r involves the variable r.
We can only sum the two terms: we have $7t-8t-8 = (7-8)t-8 = -t-8$
We can't sum this terms: -20 is a pure number, while -15p involves the variable p.
We can sum the terms, because they all involve the variable $g$ , and we have $-g-g-g = (-1-1-1)g = -3g$

7 0

3 years ago

Help please. If correct I’ll mark as brainliest but I rlly need help.

kykrilka [37]

Answer:

Step-by-step explanation:

x +3x+5x - 54 = 360

x +3x+5x = 360 + 54

9x = 414

x= 46

4 0

3 years ago

A company's revenue (in dollars) can be modeled by the function

Tju [1.3M]

R(p) = -15p² + 200p + 10,000
To find the maximum of the function, we take the first derivative and equate to 0:

R'(p) = -30p + 200
0 = -30p + 200
p = 6.67

A price of $6.67 will maximize revenue.

6 0

3 years ago

Simplify 6/6^1/4 rational exponents

White raven [17]

Answer:

we conclude that:

$\frac{6}{6^{\frac{1}{4}}}=6^{\frac{3}{4}}$