Answer:
The equation of line with given slope that include given points is 3 y + x - 20 = 0
Step-by-step explanation:
According to Cora , if we know the slope and points on a line then we can write the equation of a line .
Since , The equation of line in slope-intercept form is
y = m x + c
<u>Where m is the slope of line , and if we know the points ( x , y ) which satisfy the line then constant term c can be get and the equation of line can be formed .</u>
So , From the statement said above it is clear that she is correct .
Now , Again
Given as :
Slope of a line is m = - 
That include points ( 2 , 6 )
Now from the equation of line as y = m x + c
∴ 6 = -
( 2 ) + c
Or, 6 = -
+ c
So , c = 6 +
or, c =
∴ c =
So, The equation of line can be written as
y = -
x +
Or, 3 y = - x + 20
I.e 3 y + x - 20 = 0
Hence The equation of line with given slope that include given points is 3 y + x - 20 = 0 Answer
I'm not sure about this but will give it a try:
Let f(n) = 2xⁿ - 2
Then f(3) = 2x³ - 2
So, f(2) = 2x² - 2
2/10 in simplest form is 0.2
D 28/4=7 that is the answer for the question
Answer:
(- 4, - 12 ) , (4, 12 )
Step-by-step explanation:
Given the 2 equations
y = 3x → (1)
y = x² + 3x - 16 → (2)
Substitute y = x² + 3x - 16 into (1)
x² + 3x - 16 = 3x ( subtract 3x from both sides )
x² - 16 = 0 ( add 16 to both sides )
x² = 16 ( take the square root of both sides )
x = ±
= ± 4
Substitute these values into (1) for corresponding values of y
x = - 4 : y = 3 × - 4 = - 12 ⇒ (- 4, - 12 )
x = 4 : y = 3 × 4 = 12 ⇒ (4, 12 )