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Rama09 [41]
3 years ago
7

A librarian is putting 87 books in boxes for

Mathematics
2 answers:
emmainna [20.7K]3 years ago
8 0

Answer:

there will be 8 boxes filled and 7 extras books

evablogger [386]3 years ago
3 0

Answer:

Hi how are you doing today Jasmine

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Which of the following are equivalent to
Anon25 [30]

Answer:

a b

Step-by-step explanation:

6 0
4 years ago
If you are given the graph of h(x) = log. x, how could you graph m(x) = log2(x+3)?
Agata [3.3K]

Answer:

Option (d).

Step-by-step explanation:

Note: The base of log is missing in h(x).

Consider the given functions are

h(x)=\log_2x

m(x)=\log_2(x+3)

The function m(x) can be written as

m(x)=h(x+3)           ...(1)

The translation is defined as

m(x)=h(x+a)+b           .... (2)

Where, a is horizontal shift and b is vertical shift.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

On comparing (1) and (2), we get

a=3,b=0

Therefore, we have to translate each point of the graph of h(x) 3 units left to get the graph of m(x).

Hence, option (d) is correct.

3 0
3 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[-8,6]. B=[
just olya [345]

Answer:

49°

Step-by-step explanation:

Given vectors:

a = [-8, 6]

B = [√7, 3]

θ = ?

To find the angle between the two vectors, we will be using the formula,

                                   a.B = |a||B|cosθ

For simplicity, it is good to first calculate the dot product, and the magnitudes. Then we will substitute the values of the dot product, and the magnitudes of the vectors to solve for the angle.

Calculating the dot product

         a.B = (-8, 6) . (√7, 3)

               = (-8 × √7) + (6 × 3)

               = -8√7 + 18

               = 18 - 8√7

               = 10√7

Calculating the magnitude the vectors

1. The magnitude of vector (-8, 6)    

                |a| = \sqrt{(-8)^{2} + 6^{2}}

                |a| = \sqrt{64 + 36}

                |a| = \sqrt{100}

                |a| = 10

2. The magnitude of vector (√7, 3)

                |B| = \sqrt{(\sqrt{7})^{2} + 3^{2}}

                |B| = \sqrt{7 + 9}

                |B| = \sqrt{16}

                |B| = 4

Calculating the angle between the vectors,

                cosθ = \frac{a.B}{|a||B|}

                cosθ = \frac{10\sqrt{7}}{10 * 4}

                cosθ = 0.6614

                θ = cos⁻¹0.6614

                θ = 48.59°

                θ = 49°

5 0
4 years ago
If you have a right triangle is 10 cm² and one of the legs is 4 cm find the length of the other leg
lesya [120]

If you are saying that the hypotenuse is 10 cm the you have to solve the following equation using the Pythagorean theory.

4^2 + b^2 = 10^2

16 + b^2 = 100

16 - 16 + b^2 = 100 - 16

b^2 = 84

Find \sqrt{84\\

5 0
3 years ago
Read 2 more answers
Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
levacccp [35]

Answer:

Option A

Step-by-step explanation:

Because the cosine of beta is : cos(B) = BC/AB

4 0
3 years ago
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