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3 years ago

Help ASAP please!!!

Mathematics

2 answers:

masya89 [10]3 years ago

7 0

Total revenue the previous year would be $46,355

Akimi4 [234]3 years ago

7 0

Answer:

$50,000

Step-by-step explanation:

Let's make an equation.

<h2>1.27x = 63,500</h2><h3>One unit of x would be the total revenue from the previous year.</h3><h3>Divide by (100/127, the reciprocal of 1.27) on each side to find out x.</h3><h2>x = 50,000</h2><h2>The total revenue from the previous year was $50,000.</h2>

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Vesnalui [34]

Answer:

THank u so much for the free points

Step-by-step explanation:

8 0

2 years ago

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An item is regularly priced at $85 . it is on sale for 60% off the regular price. how much (in dollars) is discounted from the r

Alex_Xolod [135]

100% - 60% = 40%
40% = 85
1% = 85 / 40
100% = 85/ 40 × 100
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3 years ago

19) Given that f(x)x² - 8x+ 15x² - 25find the horizontal and vertical asymptotes using the limits of the function.A) No Vertical

Tems11 [23]

EXPLANATION

Since we have the function:

$f(x)=\frac{x^2-8x+15}{x^2}$

Vertical asymptotes:

$For\:rational\:functions,\:the\:vertical\:asymptotes\:are\:the\:undefined\:points,\:also\:known\:as\:the\:zeros\:of\:the\:denominator,\:of\:the\:simplified\:function.$

Taking the denominator and comparing to zero:

$x+5=0$

The following points are undefined:

$x=-5$

Therefore, the vertical asymptote is at x=-5

Horizontal asymptotes:

$\mathrm{If\:denominator's\:degree\:>\:numerator's\:degree,\:the\:horizontal\:asymptote\:is\:the\:x-axis:}\:y=0.$ $If\:numerator's\:degree\:=\:1\:+\:denominator's\:degree,\:the\:asymptote\:is\:a\:slant\:asymptote\:of\:the\:form:\:y=mx+b.$ $If\:the\:degrees\:are\:equal,\:the\:asymptote\:is:\:y=\frac{numerator's\:leading\:coefficient}{denominator's\:leading\:coefficient}$ $\mathrm{If\:numerator's\:degree\:>\:1\:+\:denominator's\:degree,\:there\:is\:no\:horizontal\:asymptote.}$ $\mathrm{The\:degree\:of\:the\:numerator}=1.\:\mathrm{The\:degree\:of\:the\:denominator}=1$ $\mathrm{The\:degrees\:are\:equal,\:the\:asymptote\:is:}\:y=\frac{\mathrm{numerator's\:leading\:coefficient}}{\mathrm{denominator's\:leading\:coefficient}}$ $\mathrm{Numerator's\:leading\:coefficient}=1,\:\mathrm{Denominator's\:leading\:coefficient}=1$ $y=\frac{1}{1}$ $\mathrm{The\:horizontal\:asymptote\:is:}$ $y=1$

In conclusion:

$\mathrm{Vertical}\text{ asymptotes}:\:x=-5,\:\mathrm{Horizontal}\text{ asymptotes}:\:y=1$

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1 year ago

Find the product. If possible, rename the product as a mixed number or a whole number 7/2 x 9/10

tamaranim1 [39]

Step-by-step explanation:

7/9×9/10

63/20

3 3/20

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3 years ago

Need help on this plzz

GrogVix [38]

The answer is A
I hope this helps

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3 years ago