All categories

2 years ago

Graph the solution c-12>-16

Mathematics

1 answer:

timofeeve [1]2 years ago

7 0

Answer:

c-12>-16

+12

C > - 4

So, c is greater than - 4.

Draw a number line. (Pick starting point of your choice. I. E. - 6 to 4)

Draw a circle at - 4.

Draw a horizontal line from the circle at - 4 to 2, for example.

Draw an arrow head on the line.

(BTW the arrow head & horizontal line can exceed 2 if you want it to; as long as your showing clearly C can be any number greater than - 4, with arrow pointing to the right as shown below)

o--------------------->

o---------------------> -4 - 3 - 2 - 1 0 1 2

Hope this helps!

You might be interested in

In the equation x+12=30 does x=16 explain your answer

denpristay [2]

No x does NOT equal 16. you would substitute x for 16 which gives you 16+12. That equals 28 not 30. The correct answer is x=18

4 0

2 years ago

What is the solution set? 12x−6.5>12 Enter your answer in the box

Jlenok [28]

X > 1.54 this is the answer hope i helped

6 0

3 years ago

Read 2 more answers

Any body want to talk

Liula [17]

Answer:

wasssssssssssup

have a good day :)

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

F log10x = 3, then x =

kondor19780726 [428]

Answer: 100

Step-by-step explanation:

Reminder that log with no given base is actually log base 10

$log_{10}10x=3\\\\10x = 10^3\\\\x = \dfrac{10^3}{10}\\\\\\x = 10^2\\\\x = 100$

7 0

3 years ago

A basket contains three green apples and six red apples. three of the apples are selected at random. what is the probability tha

Dominik [7]

Solution: We are given that a basket contains three green apples and six red apples.

Three apples are randomly selected from the basket.

Now the probability of selecting first apple green is $\frac{3}{9} =\frac{1}{3}$

The probability of selecting second apple green is $\frac{2}{8} = \frac{1}{4}$

The probability of selecting third apple green is $\frac{1}{7}$

Therefore, the probability of selecting three green apples is:

$\frac{1}{3} \times\frac{1}{4} \times\frac{1}{7} =0.0119$ or 1.19%

Now how many red apples must be added to the basket in order to make the above probability smaller than 0.1%

If we add 11 red apples to the basket, then there will be 17 red apples and 3 green apples in the basket. Therefore, the probability of selecting three green apples if three apples are randomly selected is:

$\frac{3}{20} \times\frac{2}{19} \times\frac{1}{18} = 0.0009$ or 0.09%

Therefore, we need to add 11 red apples to the basket to make this probability smaller than 0.1%

8 0

3 years ago