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nadya68 [22]
3 years ago
11

The radius of a 10 inch right circular cylinder is measured to be 4 inches, but with a possible error of ±0.1 inch. What is the

resulting possible error in the volume of the cylinder? Include units in your answer.
Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0

Answer:


Step-by-step explanation:

Given that a cylinder has radius equal to 10 inches but measured to be 4 inches

The margin of error is +1 or -1 meaning that

the radius can take values between 3.9 and 4.1 inches

Volume of cylinder =\pir^{2} h\\=100\pih

where h is height

The above is the actual volume.

Measured volume would be between radius 3.9 and 4.1 inches

i.e. Measured volume =\pi(3.9)^2 h

Volume would be between these two values

Possible error =100-15.21 = 84.79 pi h

OR = 84.19 pi h cubic inches

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What is the role of PI in finding the circumference of a circle
Katarina [22]

Answer:

PI is part of the formula for the circumference.

Step-by-step explanation:

The formula is c=2π r.

Hope it helps!

5 0
3 years ago
3) A tour trolley covers a distance of 8.5 miles in of an hour.
sp2606 [1]

Answer:

a) Ans: 8.5 miles per hour

b) Ans: 46.75 miles

Step-by-step explanation:

a) Speed = Distance/Time

8.5/1h = 8.5 miles per hour

b) Distance = Speed x Time

8.5 miles per hour x 5.5h = 46.75 miles

5 0
3 years ago
Someone please help correct answers only
sergeinik [125]
I think the correct answer is P=3
................

8 0
3 years ago
Read 2 more answers
The minimum/maximum value of the function y = a(x − 2)(x − 1) occurs at x = d, what is the value of d?
daser333 [38]

Answer:

d=\frac{3}{2}=1.5

Step-by-step explanation:

We have the function:

y=a(x-2)(x-1)

And we want to find x=d for which the minimum/maximum value will occur.

Notice that our function is a quadratic in factored form.

Remember that the minimum/maximum value always occurs at the vertex point.

And remember that the x-coordinate of the vertex is the axis of symmetry.

Since a quadratic is always symmetrical on both sides of its axis of symmetry, a quadratic’s axis of symmetry is the average of the two roots/zeros of the quadratic.

Therefore, the value x=d such that it produces the minimum/maximum value is the average of the two roots.

Our factors are <em>(x-2) </em>and <em>(x-1)</em>.

Therefore, our roots/zeros are <em>x=1, 2</em>.

So, the average of them are:

d=\frac{1+2}{2}=3/2=1.5

Therefore, regardless of the value of <em>a</em>, the minimum/maximum value will occur at <em>x=d=1.5</em>.

Alternative Method:

Of course, we can also expand to confirm our answer. So:

y=a(x^2-2x-x+2)\\y=a(x^2-3x+2)\\y=ax^2-3ax+2a

The x-coordinate of the vertex is still going to be the place where the minimum/maximum is going to occur.

And the formula for the vertex is:

x=-\frac{b}{2a}

So, we will substitute <em>-3a</em> for <em>b</em> and <em>a</em> for <em>a</em>. This yields:

x=-\frac{-3a}{2a}=\frac{3}{2}=1.5

Confirming our answer.

4 0
3 years ago
Given a rectangle with an area of 20 square units, if the width is x units and the length is x + 1 units, what is the difference
ollegr [7]

Answer: 1unit.

Step-by-step explanation:

Area of the rectangle

A = length × width

Since the area = 20 and the width is x and the length is x + 1.

We now substitute for the values in the above formula and solve for x

20 = x × x + 1

20 = x( x + 1 ), we now open

20 = x² + x , then re arrange.

x² + x - 20 = 0, this is a quadratic equation.we solve for x using quadratic means

Here, I am going to solve using factorization by grouping

x² + x - 20 = 0

x² + 5x - 4x - 20 = 0

x( x + 5 ) - 4( x + 5 ) = 0

( x + 5 )( x - 4 ). = 0

Therefore, the solution for x will be

x = -5 or 4, but x can not be -5 ( negative), so x = 4.

Now the difference between width and the length can easily be calculated from the above,

Width = 4 (x) , and length = 5 (4 + 1),

Now difference will be

5 - 4 = 1unit.

5 0
3 years ago
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