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sesenic [268]
3 years ago
8

A wedding website states that the average cost of a wedding is $25,809. One concerned bride hopes that the average is less than

reported. To see if her hope is correct, she surveys 46 recently married couples and finds that the average cost of weddings in the sample was $24,638. Assuming that the population standard deviation is $5531, is there sufficient evidence to support the bride’s hope at the 0.10 level of significance?
Step 1 of 3 : State the null and alternative hypotheses for the test. Fill in the blank below.
H0Ha: μ=25,809: μ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯25,809
Step 2 of 3 : Find the test statistic
Step 3 of 3 : What is the conclusion?
Mathematics
1 answer:
lapo4ka [179]3 years ago
6 0

Answer:

1)

Null hypothesis            H₀ : μ = 25,809

Alternative hypothesis H₁ : μ < 25,809

2) Test Statistic = -1.44

3) Conclusion:

The result is significant, there is sufficient evidence to support the bride’s hope at the 0.10 level of significance.

Step-by-step explanation:

Given the data in the question;

Sample mean x" = 24,638

sample size n = 46

standard deviation σ = 5531

level of significance ∝ = 0.10

NULL and ALTERNATIVE HYPOTHESIS

Null hypothesis            H₀ : μ = 25,809

Alternative hypothesis H₁ : μ < 25,809

TEST STATISTICS

Z = (x"-μ) / σ√n

we substitute

Z = (24,638 - 25,809) / (5531/√46)

Z = -1171 / 815.5

Z = -1.44

Test Statistic = -1.44

Now, from normal z-table;

P-value = P( Z < -1.44 ) = 0.0749

P-value = 0.0749

Since P-value ( 0.0749 ) is less than level of significance ( 0.10 ), we reject H₀.

Conclusion:

The result is significant, there is sufficient evidence to support the bride’s hope at the 0.10 level of significance.

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ohaa [14]
The answers are A and C. Glad I could help!
4 0
3 years ago
Hi, can you help me answer this question please, thank you!
matrenka [14]

It is given that the sample size is 17.

So degrees of freedom is 16.

The confidence level is 80%.

Use the t table or a tool to find the critical t value as below:

The one tail t value for 80 percent confidence is 0.865 using t table.

So the critical value is 0.865.

8 0
1 year ago
An equation is shown below: 8(2x – 14) + 13 = 4x – 27 Part A: Write the steps you will use to solve the equation, and explain ea
blsea [12.9K]
1) Distribute 8(2x-14) + 13 = 4x - 27 then simplify like terms to get: 16x - 99 = 4x - 27.
2) Subtract 4x on both sides and at the same time add 99 to both sides to get: 12x=72.
3) Divide both sides by 12 to get x=6.
PART B: 6 makes the equation true because you just solved for it.
8 0
3 years ago
Suppose you are conducting a survey about the amount grocery store baggers are tipped for helping customers to their cars .for a
ELEN [110]

Using the Empirical Rule and the Central Limit Theorem, we have that:

  • About 68% of the sample mean fall with in the intervals $1.64 and $1.82.
  • About 99.7% of the sample mean fall with in the intervals $1.46 and $2.

<h3>What does the Empirical Rule state?</h3>

It states that, for a normally distributed random variable:

  • Approximately 68% of the measures are within 1 standard deviation of the mean.
  • Approximately 95% of the measures are within 2 standard deviations of  the mean.
  • Approximately 99.7% of the measures are within 3 standard deviations of the mean.

<h3>What does the Central Limit Theorem state?</h3>

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem, the standard deviation of the distribution of sample means is:

s = \frac{0.657}{\sqrt{50}} = 0.09

68% of the means are within 1 standard deviation of the mean, hence the bounds are:

  • 1.73 - 0.09 = $1.64.
  • 1.73 + 0.09 = $1.82.

99.7% of the means are within 3 standard deviations of the mean, hence the bounds are:

  • 1.73 - 3 x 0.09 = $1.46.
  • 1.73 + 3 x 0.09 = $2.

More can be learned about the Empirical Rule at brainly.com/question/24537145

#SPJ1

5 0
2 years ago
a car rent is $240 per week plus $1.00 per mile. Find the rental cost for a two week trip of 500 miles for a group of three peop
tankabanditka [31]

Answer:

I'm not sure if you mean each person has a car for 2 weeks and travels 500 miles each but if so the rental cost is $2,940.

If it is just one car for all 3 people the rental cost is $980

Step-by-step explanation:

renatl cost = r

weeks = w

miles = m

the equation would be  r = $240w + $1m

and if there are 3 people you mulitply the answer by 3

5 0
3 years ago
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