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denis23 [38]
3 years ago
10

What is the distance between (8,-3) and (4,-7) ?​

Mathematics
1 answer:
galina1969 [7]3 years ago
8 0

Answer:

The answer is

<h3>4 \sqrt{2}   \: \:  \: or \:  \:  5.656 \:  \:  \: units</h3>

Step-by-step explanation:

The distance between two points can be found by using the formula

<h3>d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(8,-3) and (4,-7)

The distance between them is

<h3>d =  \sqrt{ ({8 - 4})^{2}  +  ({ - 3 + 7})^{2} }  \\  =  \sqrt{ ({4})^{2} + ( { - 4})^{2}  }  \\  =  \sqrt{16 + 16}  \\  =  \sqrt{32}</h3>

We have the final answer as

<h3>4 \sqrt{2}   \: \:  \: or \:  \:  5.656 \:  \:  \: units</h3>

Hope this helps you

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