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3 years ago

If s(x) = x-7 and f(x) = 4x? – X+3, which expression is equivalent to (tos)(x)?

Mathematics

1 answer:

lesya692 [45]3 years ago

4 0

Answer:

4(x-7)^2-(x-7)+3 (Assuming t is f)

Step-by-step explanation:

Let s(x)=x-7 and t(x)=4x^2-x+3 .

(t o s)(x)=t(s(x))=t(x-7)

Before I continue this means replace the orginal x in t with x-7.

This will then give you

4(x-7)^2-(x-7)+3

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alexdok [17]

31. There are C(5, 2) = 10 ways to choose 2 colors from a group of 10 colors if you don't care about the order. (Here, we treat blue background with violet letters as being indistinguishable from violet background with blue letters.)

Only one of those 10 pairs is "B and V", so the probability is 1/10.
a) P(B and V) = 10%

32. The 12 inch dimension on the figure is 0 inches for the cross section. The remaining dimensions of the cross section are
c) 5 in. × 4 in.

_____
C(n, k) = n!/(k!·(n-k)!)
C(5, 2) = 5!/(2!·3!) = 5·4/(2·1) = 10

8 0

2 years ago

Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat

eimsori [14]

Answer:

There are NO real roots for this equation. The only roots have imaginary parts and therefore cannot be represented on the real x-axis.

Step-by-step explanation:

We notice that the expression on the left of the equation is a quadratic with leading term $2x^2$ , which means that its graph is that of a parabola with branches going up.

Therefore, there can be three different situations:

1) if its vertex is ON the x axis, there would be one unique real solution (root) to the equation.

2) if its vertex is below the x-axis, the parabola's branches are forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will have NO real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently.

We recall that the x-position of the vertex for a quadratic function of the form $f(x)=ax^2+bx+c$ is given by the expression:

$x_v=\frac{-b}{2a}$

Since in our case $a=2$ and $b=-3$ , we get that the x-position of the vertex is:

$x_v=\frac{-b}{2a}\\x_v=\frac{-(-3)}{2(2)}\\x_v=\frac{3}{4}$

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = 3/4:

$y_v=f(\frac{3}{4})=2( \frac{3}{4})^2-3(\frac{3}{4})+4\\f(\frac{3}{4})=2( \frac{9}{16})-\frac{9}{4}+4\\f(\frac{3}{4})=\frac{9}{8}-\frac{9}{4}+4\\f(\frac{3}{4})=\frac{9}{8}-\frac{18}{8}+\frac{32}{8}\\f(\frac{3}{4})=\frac{23}{8}$

This is a positive value for y, therefore we are in the situation where there is NO x-axis crossing of the parabola's graph, and therefore no real roots.

We can though estimate a few more points of the parabola's graph in order to complete the graph as requested in the problem. For such we select a couple of x-values to the right of the vertex, and a couple to the right so we can draw the branches. For example: x = 1, and x = 2 to the right; and x = 0 and x = -1 to the left of the vertex:

$f(-1) = 2(-1)^2-3(-1)+4= 2+3+4=9\\f(0)=2(0)^2-3(0)+4=0+0+4=4\\f(1)=2(1)^2-3(-1)+4=2-3+4=3\\f(2)=2(2)^2-3(2)+4=8-6+4=6$

See the graph produced in the attached image.

4 0

2 years ago

If the length of the side of a square is 6 cm,then the area will be equal to ________

Feliz [49]

Answer:

36 centimeters squared.

Step-by-step explanation:

Use the formula for the area of a square.

$A=s^2$

$A=(6)^2$

$A=6 \times 6=36$

3 0

2 years ago

Read 2 more answers

What is the value of the 24th term is the fourth term is 6 and the eighth term is 8

Alina [70]

The value of the 24th term is 16.

<h3>Arithmetic progression:</h3>

aₙ = a + (n - 1)d

where

a = first term

d = common difference

n = number of terms

Therefore,

6 = a + 3d

8 = a + 7d

let's find a and d

2 = 4d

d = 2 / 4

d = 1 / 2

6 = a + 3 / 2

a = 6 - 3 /2

a = 4.5

Therefore, the 24th term can be found as follows;

24th term = 4.5 + 23(0.5)

24th term = 4.5 + 11.5

24th term = 16

learn more on arithmetic progression here; brainly.com/question/9882454

4 0

2 years ago

Write (5/3)³ as a quotient of powers.

Oxana [17]

Answer:

The number (5/3)³ written as a quotient of powers is; 5³/3³

According to the question;

We are required to determine write the number, (5/3)³ as a quotient of powers

The number (5/3)³ can be evaluated as;

= 125/27

= 5³/3³

Step-by-step explanation:

3 0

2 years ago