Answer:
School Sucks!
Step-by-step explanation:
Half of this stuff you will never use in real life!
A circle’s standard form of an equation is:
(x-h)^2 + (y-k)^2 = radius^2
Plug in h and k immediately because that is something you automatically know. H and k are derived from the center of the circle. The center of the circle is (h,k). Don’t get tripped up though, your center of a circle has negative coordinates. When you have two negatives, they become positive.
So now you have:
(x+4)^2 + (y-2)^2 = radius^2
So figure out what the radius is. Use the distance formula to find out. You have a change of 5 from -4 to 1 in x. You have a change of 2 from 2 to 4 in y. Distance formula has the distance as the square root of x distance squared and y distance squared. That would mean that the distance/radius is equal to the square root of (25 + 4). 5 squared is 25 while 2 squared is 4.
The radius of the circle is equal to the square root of (29). However, looking back at the circle equation the radius should be squared for the equation. Square root of 29 squared gets you 29.
Plug that in and you get:
(x+4)^2 + (y-2)^2 = 29
Answer:
Simplified: -4a²b²+18a³-2b³
3a(6a²-4ab²)+8a²b²-2b³
Multiply 3a by 6a² and-4ab²
18a³-12a²b²+8a²b²-2b³
combine like terms (-12a²b² and 8a²b²)
-4a²b²+18a³-2b³
Hope this helps
X+y=8
multiply the first equation by 3 to get rid of x
3x+3y=24
3x+2y=14
subtract equation 1 from 2
y=10
substitute to find the value of x
x+10=8
x=-2
Answer:
1 fish left because you have 7 and your taking away 6.
Step-by-step explanation:
7-6=1
