Answer:
equation;

Center (-4,2)
Radius is

Step-by-step explanation:
Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of

Where (h,k) is center
r is the radius
So first we group like Terms together

Add 7 to both sides


Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem

and

so we have



To find our center, h is -4 and k is 2
so the center is (-4,2)
The radius is

So the radius is 3 times sqr root of 3.
![\bf sin(x)[csc(x)-sin(x)]~~=~~cos^2(x) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(x)\left[\cfrac{1}{sin(x)}-\cfrac{sin(x)}{1} \right]\implies \underline{sin(x)}\left[\cfrac{1-sin^2(x)}{\underline{sin(x)}} \right] \\\\\\ 1-sin^2(x)\implies cos^2(x)](https://tex.z-dn.net/?f=%5Cbf%20sin%28x%29%5Bcsc%28x%29-sin%28x%29%5D~~%3D~~cos%5E2%28x%29%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20sin%28x%29%5Cleft%5B%5Ccfrac%7B1%7D%7Bsin%28x%29%7D-%5Ccfrac%7Bsin%28x%29%7D%7B1%7D%20%5Cright%5D%5Cimplies%20%5Cunderline%7Bsin%28x%29%7D%5Cleft%5B%5Ccfrac%7B1-sin%5E2%28x%29%7D%7B%5Cunderline%7Bsin%28x%29%7D%7D%20%5Cright%5D%20%5C%5C%5C%5C%5C%5C%201-sin%5E2%28x%29%5Cimplies%20cos%5E2%28x%29)
recall again, sin²(θ) + cos²(θ) = 1.
Answer:
C
Step-by-step explanation:
according to sine rule,
sin(30)/8=sin(x)/11
solving above equation will give
x=43.3
Answer:
$44487
Step-by-step explanation:
If you plug in 10 for t, you are left with the following equation:
. Hope this helps!
7/12*6/14
7*6=42
12*14=168
=42/168
=0.25 =1/4