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Ksenya-84 [330]
3 years ago
14

Will mark brainli if you give explanation

Mathematics
2 answers:
dmitriy555 [2]3 years ago
5 0

Answer:

960 ft²

Since you are doing volume, your multiplication sentence would look like

Length * Width * Height

Now, if you multiply 10 * 8 * 12, your answer will be 960 ft²

Vanyuwa [196]3 years ago
4 0

Answer:

Answer B is correct.

Step-by-step explanation:

A=2(wl+hl+hw) \\ =2·(8·10+12·10+12·8) \\ =592 {ft}^{2}

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I will give brainliest if correct!!! Please show work so I know how to do it. :)
yawa3891 [41]

Answer:

.2625

Step-by-step explanation:

logb(3) = 0.5646, logb(4) = 0.7124, and logb(5) = 0.8271

logb(5/3)

We know that logx ( y/z) = logx (y) - logz (z)

logb ( 5) - logb(3)

0.8271 - 0.5646

.2625

5 0
3 years ago
Read 2 more answers
If the triangle measure 180 degrees. What is the missing angle?
max2010maxim [7]

Answer:

116

Step-by-step explanation:

36+28=64

180-64=116

3 0
3 years ago
Read 2 more answers
Help me please (no links please)
stich3 [128]

a) This part is already complete I think..

b) This is a cuboid and lateral surface area of cuboid is: 2(lb +bh + hl)

= 2( 10 × 3 + 3 × 7 + 7 × 10)

= 2(30 + 21 + 70)

= 2 × 121 = 242 cm²

Now, the area of top & bottom: lb

= 2 × 10 × 3

= 60 cm²

Neglecting the top & bottom surface area of cuboid:

= 242 - 60

= 180 cm²

c) The total surface area us 242.. I have already done that part above...

__________________________

If i have done something wrong.. please lemme know :)

7 0
3 years ago
Please help me, very important 20 points!
kipiarov [429]

x=96


all interior angles equal 180


Subtract exterior andgles by 180 to get interior angles because they are supplementary

180-134=46

180-130=50


Get the third angle inside the triangle

180-50-46=84


subtract by 180 to get x because they are supplementary

180-84=96


Therefore x =96

4 0
3 years ago
What is the average rate of change of the function over the interval x = 0 to x = 5?
AURORKA [14]

\bf slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ f(x)= 2x^2-1\qquad \begin{cases} x_1=0\\ x_2=5 \end{cases}\implies \cfrac{f(5)-f(0)}{5-0} \\\\\\ \cfrac{[2(5)^2-1]~~-~~[2(0)^2-1]}{5}\implies \cfrac{50-(-1)}{5}\implies \cfrac{50+1}{5}\implies \cfrac{51}{5}\implies 10\frac{1}{5}

6 0
3 years ago
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