In laborador retrievers, pigment color is influenced by two genes. Gene A determines the type of pigment produced and gene B aff
ects whether the pigment gets deposited in the hair shaft. If two heterozygous black laborator retrievers were crossed and offspring were produced in a ratio of 9 black dogs to 3 brown dogs to 4 yellow dogs, what are the genotypes of the offspring?
1 answer:
Answer:
AaBb, AABb, AaBB, AABB, Aabb, aaBb, AAbb, aaBB, aabb.
Explanation:
Gene A conditions pigment type.
Gene B determines whether the pigment of A will be deposited.
Heterozygous black individuals will have the genotype AaBb.
Two heterozygous black individuals were crossed:
AaBb x AaBb
Progeny:
4 AaBb - Black
2 AABb - Black
2 AaBB - Black
1 AABB - Black
2 Aabb - yellow
2 aaBb - yellow
1 AAbb - brown
1 aaBB - brown
1 aabb - brown
<em>Hence, the genotypes of the offspring are:</em>
AaBb, AABb, AaBB, AABB, Aabb, aaBb, AAbb, aaBB, aabb.
See the attached image for the Punnet's square result of the cross.
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Answer:
<em><u>D. Cytoskeleton</u></em>
Explanation:
It is really none of these answers. The correct answer would be a microtubule which is a component of the cytoskeleton which is in the cytoplasm.
The Cell Walls are only in plant cells so that won't work. So, A wouldn't work.
Chromosomes are the things that both your parents give you as genes. They have nothing to do with keeping the structure of the cell alright.
Cytoplasm cannot be a answer choice because, the thing is in it but, it doesn't do anything with it. So C wouldn't work either
The correct answer is microtubule however, it is a component of cytoskeleton so therefore, that is your answer.
<em><u>Reference the picture below:</u></em>
