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azamat
3 years ago
12

(-5)2 - 2 x (-9) + 6​

Mathematics
1 answer:
Veronika [31]3 years ago
6 0

Answer:

This is the answer

Step-by-step explanation:

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!!!!!!!!!!!!pls answer!!!!!!!!!!!(i'm being timed)
kobusy [5.1K]

Answer:

an+4n+1

Step-by-step explanation:

Hope it helped

3 0
2 years ago
The perimeter of a right triangle is 60 feet and the area is 150 square feet. If the lengths of the sides of the triangle are ea
JulsSmile [24]

Answer:

B. 600 ft

Step-by-step explanation:

The formula for the Perimeter of a right triangle = Side a + Side b + Side c

The perimeter of a right triangle is 60 feet

If the lengths of the sides of the triangle are each multiplied by 10, what is the perimeter of the new right triangle?

Hence, the perimeter of the new right triangle = 10 × 60ft

= 600ft

Option B is the correct Option.

4 0
3 years ago
Read 2 more answers
Pls help i will mark brainleist
lara [203]

Answer:

ok so term 9 coefficent 5 term factor 1 quotient division sign sum add sign product x signf

Step-by-step explanation:

6 0
3 years ago
The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea
a_sh-v [17]
Check the picture below.

so the rhombus has the diagonals of AC and BD, now keeping in mind that the diagonals bisect each, namely they cut each other in two equal halves, let's find the length of each.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad 
C(\stackrel{x_2}{6}~,~\stackrel{y_2}{8})\qquad \qquad 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{[6-(-4)]^2+[8-(-2)]^2}\implies AC=\sqrt{(6+4)^2+(8+2)^2}
\\\\\\
AC=\sqrt{10^2+10^2}\implies AC=\sqrt{10^2(2)}\implies \boxed{AC=10\sqrt{2}}\\\\
-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
B(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad 
D(\stackrel{x_2}{4}~,~\stackrel{y_2}{0})\qquad \qquad BD=\sqrt{[4-(-2)]^2+[0-6]^2}
\\\\\\
BD=\sqrt{(4+2)^2+(-6)^2}\implies BD=\sqrt{6^2+6^2}
\\\\\\
BD=\sqrt{6^2(2)}\implies \boxed{BD=6\sqrt{2}}

that simply means that each triangle has a side that is half of 10√2 and another side that's half of 6√2.

namely, each triangle has a "base" of 3√2, and a "height" of 5√2, keeping in mind that all triangles are congruent, then their area is,

\bf \stackrel{\textit{area of the four congruent triangles}}{4\left[ \cfrac{1}{2}(3\sqrt{2})(5\sqrt{2}) \right]\implies 4\left[ \cfrac{1}{2}(15\cdot (\sqrt{2})^2) \right]}\implies 4\left[ \cfrac{1}{2}(15\cdot 2) \right]
\\\\\\
4[15]\implies 60

7 0
3 years ago
Read 2 more answers
Tell wether the angles are adjacent or vertical. Then find the value of x.
Gre4nikov [31]

Answer:

The angles are vertical

Step-by-step explanation:

x+42+2x+1=180

put the like terms together i.e 2x+x+42+1=180

you get: 3x+43=180

Take 43 to th other side of 180 i.e 3x=180-43 i.e (180-43=137)

You get 3x=137

Divide both sides by 3

you get x=45.666666666667(Round off to get 45.67)

Substitute the value of x to the angles

x+42(45.67+42=87.67)

2x+1(2(45.67)+1=92.34

Add 87.67+92.34=180

THis shows that the angles are vertical

8 0
2 years ago
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