Answer:
You kayak 255 feet farther 5 minutes on the way down the river than in 5 minutes on the way up the river
Step-by-step explanation:
Given:
The rate at which you kayak up a river = 48 feet every 30 seconds.
The rate at which you kayak down a river = 423 feet every 3 minutes
To Find:
How much farther do you kayak in 5 minutes on the way down the river than in 5 minutes on the way up the river = ?
Solution:
Let the speed with which you kayak up the river be x and the speed with which you kayak down the river be y
Then
x =
[ Converting 30 seconds to 0.5 minutes]
x = 96 feet per minute
Similarly
y =
y = 141 feet per minute
Now the distance kayaked up the river in 5 minutes
=>
=>
( in 5 minutes there are 10 30 minutes)
=>960 feet
Now the distance kayaked down the river in 5 minutes
=>
=>
( in 5 minutes there are 10 30 minutes)
=>705 feet
Thus
960-705 = 255 feet
I need more information to help
Answer:
The answer is L
Step-by-step explanation:
SOLUTION:
To begin with, let's establish that the formula of this line is in slope-intercept form as follows:
y = mx
The formula for this line isn't:
y = mx + b
This is as this line doesn't have a y-intercept ( b ) as it passes through the origin instead. This means that ( b ) would be rendered useless in this formula as it would just bring us back to the y = mx formula as displayed below:
y = mx + b
y = mx + 0
y = mx
Moving on, for ( m ), we need to find the gradient of the line as displayed below:
m = gradient
m = rise / run
m = 10 / 2
m = 5
Now, we must simply substitue ( m ) into the formula in order to obtain the equation for this line as displayed below:
y = mx
y = 5x
Therefore, the answer is:
A. y = 5x
Perimeter = 24
triangle perimeter = 2W + 2L
24= 2W + 2L
12 = W + L
L= 12-W
AREA = W*L
AREA = (W)(12-W)
A = 12W-W^2
maximum occurs when you take the derivative
d/dw=12-2w = 0
w=6
after this i think we can say 6 * 6 = 36 is the maximum area.. not to sure, havent done a problem like this in a while
hope this helps
or if we know what w=6 we can find L
L = 12-w which we still get 6<span />