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bonufazy [111]
4 years ago
5

Can someone please help me

Mathematics
2 answers:
Ulleksa [173]4 years ago
5 0

Answer:

Step-by-step explanation:

1) 4 : 7   ? 12 : 21

If product of mean is equal to product of extremes, then they are proportion

Product of extremes = 4*21  = 84

Product of mean = 7 * 12 = 84

Product of extremes = Product of mean

They are in proportion

4 : 7 :: 12 : 21

2) 2 : 3 ? 3: 2

Product of extremes = 2*2 = 4

Product of mean = 3*3 = 9

Product of extremes ≠ Product of mean

They are not in proportion

2 : 3 ≠ 3 : 2

3) 3/4 ?  8/6

3 : 4 ?  8:6

Product of extremes = 3 * 6   = 18

Product of mean = 4 * 8 = 24

Product of extremes ≠ Product of mean

They are not in proportion

3 : 4 ≠ 8 : 6

4) 1/5  ? 5/25

1:5  ? 5 : 25

Product of extremes = 1 * 25 = 25

Product of mean = 5 * 5 = 25

Product of extremes = Product of mean

They are in proportion

1 : 5  :: 5 : 25

grandymaker [24]4 years ago
3 0

Answer:

1) Yes

Product of Means = Product of Extremes

4 × 21 = 7 × 12

84 = 84

2) No

Product of Means = Product of Extremes

2 × 2 = 3 × 3

4 ≠ 9

3) No

Cross multiplying

3 × 6 = 4 × 8

18 ≠ 32

4) Yes

Cross Multiplying

1 × 25 = 5 × 5

25 = 25

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/sqrt{4x+15=3/sqrt{x}<br><br>what does x equal?
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Answer:

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Step-by-step explanation:

Multiply both sides by x to get rid or the denominator: \sqrt{4x+15}=3\sqrt{x}

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(2x+1)(x^2+8x-3)<br> help standard form​
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Answer:

2x^3+17x^2+2x-3

Step-by-step explanation:

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The Boffo Product Company sells a waffle iron on which they have done product testing. They have determined that the amount of t
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Answer:

They should warranty the product for 7 years if they want no more than 6.7% of the waffle irons to fail within that time.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The average waffle iron lasts for 12 years and one standard deviation is 8 months.

Measuring the time in months, we have that \mu = 12*8 = 96 and \sigma = 8

How long should they warranty the product for if they want no more than 6.7% of the waffle irons to fail within that time?

This is X when Z has a p-value of 0.067, so X when Z = -1.5. Then

Z = \frac{X - \mu}{\sigma}

-1.5 = \frac{X - 96}{8}

X - 96 = -1.5*8

X = 84

84 months = 7 years.

They should warranty the product for 7 years if they want no more than 6.7% of the waffle irons to fail within that time.

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