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bonufazy [111]
3 years ago
5

Can someone please help me

Mathematics
2 answers:
Ulleksa [173]3 years ago
5 0

Answer:

Step-by-step explanation:

1) 4 : 7   ? 12 : 21

If product of mean is equal to product of extremes, then they are proportion

Product of extremes = 4*21  = 84

Product of mean = 7 * 12 = 84

Product of extremes = Product of mean

They are in proportion

4 : 7 :: 12 : 21

2) 2 : 3 ? 3: 2

Product of extremes = 2*2 = 4

Product of mean = 3*3 = 9

Product of extremes ≠ Product of mean

They are not in proportion

2 : 3 ≠ 3 : 2

3) 3/4 ?  8/6

3 : 4 ?  8:6

Product of extremes = 3 * 6   = 18

Product of mean = 4 * 8 = 24

Product of extremes ≠ Product of mean

They are not in proportion

3 : 4 ≠ 8 : 6

4) 1/5  ? 5/25

1:5  ? 5 : 25

Product of extremes = 1 * 25 = 25

Product of mean = 5 * 5 = 25

Product of extremes = Product of mean

They are in proportion

1 : 5  :: 5 : 25

grandymaker [24]3 years ago
3 0

Answer:

1) Yes

Product of Means = Product of Extremes

4 × 21 = 7 × 12

84 = 84

2) No

Product of Means = Product of Extremes

2 × 2 = 3 × 3

4 ≠ 9

3) No

Cross multiplying

3 × 6 = 4 × 8

18 ≠ 32

4) Yes

Cross Multiplying

1 × 25 = 5 × 5

25 = 25

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Answer:

7

Step-by-step explanation:

56=8*7\\8-7=1The width is smaller, so it is 7.

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Radda [10]
Hi, these equations are pretty easy actually, first thing you should know when working with variables is that you always want to leave the variable alone, let's take the third excersise for example, 12x + 2 = 146. Here you just do the opposite on the other side of the equation depending if the number is positive or negative. Since x is being multiplied by 12 you first get rid of the 2, since its positive you subtract it to 146. Now the answer should be 12x = 144. Now since you're multiplying 12 to x you just divide 12 from 144, 144/12 = 12
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mezya [45]
Here! not sure if it's right but i'm pretty confident. boom

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Please help i dont understand what its asking
Arisa [49]

Multiply both the numerator and denominator by 2+\sqrt3, which is called the "conjugate" of 2-\sqrt3:

\dfrac{5+\sqrt3}{2-\sqrt3}\cdot\dfrac{2+\sqrt3}{2+\sqrt3}

Why do we pick this number? Recall the difference of squares factorization:

a^2-b^2=(a-b)(a+b)

Now replace a=2 and b=\sqrt3. Then

(2-\sqrt3)(2+\sqrt3)=2^2-(\sqrt3)^2=4-3=1

So in your fraction, you end up with

\dfrac{5+\sqrt3}{2-\sqrt3}=\dfrac{(5+\sqrt3)(2+\sqrt3)}1=(5+\sqrt3)(2+\sqrt3)

Finally, just expand the product.

(5+\sqrt3)(2+\sqrt3)=10+7\sqrt3+(\sqrt3)^2=\boxed{13+7\sqrt3}

7 0
2 years ago
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