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bonufazy [111]
3 years ago
5

Can someone please help me

Mathematics
2 answers:
Ulleksa [173]3 years ago
5 0

Answer:

Step-by-step explanation:

1) 4 : 7   ? 12 : 21

If product of mean is equal to product of extremes, then they are proportion

Product of extremes = 4*21  = 84

Product of mean = 7 * 12 = 84

Product of extremes = Product of mean

They are in proportion

4 : 7 :: 12 : 21

2) 2 : 3 ? 3: 2

Product of extremes = 2*2 = 4

Product of mean = 3*3 = 9

Product of extremes ≠ Product of mean

They are not in proportion

2 : 3 ≠ 3 : 2

3) 3/4 ?  8/6

3 : 4 ?  8:6

Product of extremes = 3 * 6   = 18

Product of mean = 4 * 8 = 24

Product of extremes ≠ Product of mean

They are not in proportion

3 : 4 ≠ 8 : 6

4) 1/5  ? 5/25

1:5  ? 5 : 25

Product of extremes = 1 * 25 = 25

Product of mean = 5 * 5 = 25

Product of extremes = Product of mean

They are in proportion

1 : 5  :: 5 : 25

grandymaker [24]3 years ago
3 0

Answer:

1) Yes

Product of Means = Product of Extremes

4 × 21 = 7 × 12

84 = 84

2) No

Product of Means = Product of Extremes

2 × 2 = 3 × 3

4 ≠ 9

3) No

Cross multiplying

3 × 6 = 4 × 8

18 ≠ 32

4) Yes

Cross Multiplying

1 × 25 = 5 × 5

25 = 25

You might be interested in
We discovered that 650 GSS respondents in 2006 watched television for an average of 2.98 hrs/day, with a standard deviation of 2
Aliun [14]

Answer:

a) 2.09167

b) 0.2

c) 130 correspondents

d) 5.38 hours per day

e) 69%

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean = 2.98hrs/day, Standard Deviation = 2.4

a) What is the Z score for a person who watches more than 8 hrs/day.

z = 8 - 2.98/2.4

= 2.09167

b) What proportion of people watch 5 hrs/day or more television?

z = 5 - 2.98/2.4

z = 0.84167

Determining the Probabilityvalue from Z-Table:

P(x<5) = 0.80001

The proportion of people watch 5 hrs/day or more television

P(x>5) = 1 - P(x<5) = 0.19999

Approximately = 0.2

c) How many does this correspond to in the sample?

From the question above, we are told that: there are 650 GSS respondents in 2006 watched television

Hence the proportion that corresponds to Question b is

0.2 × 650

= 130 correspondents

Therefore, 130 correspondents watch 5 hrs a day or more television

d) What number of television hours per day corresponds to a Z = +1.

z score formula is given as:

z = (x-μ)/σ

Z = +1

x = unknown

Mean = 2.98

Standard deviation = 2.4

Hence:

1 = x - 2.98/2.4

Cross Multiply

1 × 2.4 = x - 2.98

2.4 = x - 2.98

2.4 + 2.98 + x

= 5.38 hours per day.

e)What is the percentage of people who watch between 1 and 6 hours of television per day?

For x = 1

z = 1 - 2.98/2.4

z = -0.825

Probability value from Z-Table:

P(x= 1) = 0.20469

For x = 6

z = 6 - 2.98/2.4

z = 1.25833

Probability value from Z-Table:

P(x = 6) = 0.89586

The percentage of people who watch between 1 and 6 hours of television per day is calculated as:

P(x = 6) - P(x = 1)

0.89586 - 0.20469

= 0.69117

Converting to percentage,

0.69117 × 100%

= 69.117%

To the nearest whole number = 69%

Therefore, 69% of the people who watch between 1 and 6 hours of television per day

3 0
3 years ago
Ms. Goodwin earns $2570 for each 2-wk pay period. How much will she make in 28 wks?​
Salsk061 [2.6K]
$35,980 would be the correct answer.
$2570x14(paid bi weekly)
8 0
3 years ago
Can you PLEASE help with problem 4. (IF YOU KNOW IT)
Andru [333]
The total was $29. 
1. Write an equation. 24+(2.50*2)= x
2. Solve your equation using PEMDAS
       *2.5*2=5
       *5+24=
3. Simplify equation. 
   5+24=29
4 0
3 years ago
Nidhi is allowed to watch 2.5 hours of TV on Saturday If her favorite Tv show lasts for 24 minutes each, how many full episodes
bekas [8.4K]

Answer:

6 full episodes

Step-by-step explanation:

You will need to convert 2.5 hours to minutes and divide by 24. Round to the nearest whole number.

4 0
2 years ago
The questions are in the pic the other answer is 356
Andru [333]
The answer to this question is 356
4 0
3 years ago
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