Ask question

Ask question

All categories

3 years ago

13

Danielle has taken five math tests so far this year. The tests are out of twenty points, and she has gotten the following scores

. 17, 19, 20, 14, 16 What is the median of her scores? 17.2 no mode 6 17

2 answers:

dusya [7]3 years ago

6 0

14, 16, 17, 19, 20
17 is the middle one so the answer is 17

Hope this helps :)

Tpy6a [65]3 years ago

4 0

17 would be the median of her scores.
Hope this helps!
~Mistermistyeyed.

You might be interested in

What is the fourth term in the binomial expansion of (2x – y) 7?

nata0808 [166]

Answer:

$(7C4) (2x)^4 (-y)^{7-4}$

And replacing we got:

$35 (2^4) x^4 (-y)^{-3}$

And then the final term would be:

$-560 x^4 y^3$

Step-by-step explanation:

For this case we have the following expression:

$(2x-y)^7$

And we can use the binomial theorem given by:

$(x+y)^n =\sum_{k=0}^n (nCk) x^k y^{n-k}$

And for this case we want to find the fourth term and using the formula we have:

$(7C4) (2x)^4 (-y)^{7-4}$

And replacing we got:

$35 (2^4) x^4 (-y)^{-3}$

And then the final term would be:

$-560 x^4 y^3$

8 0

2 years ago

A pound of clementines costs $2.49 and ms. wild buys 1.8 pounds. how much did she spend?

Ann [662]

Answer:

i believe she spent $4.482 on clementines

6 0

2 years ago

I JUST NEED HELP PLEASE!! AHH!!~∆~

mafiozo [28]

Answer:

Step-by-step explanation:

take theta as reference angle

using sin rule

sin theta=opposite/hypotenuse

sin theta=5/13

sin theta=0.38

theta=sin 23

therefore the value of theta is 23 degree

8 0

2 years ago

Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10

Alenkasestr [34]

Answer: The correct option is (D) SET 4.

Step-by-step explanation: We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 : 14 cm, 5 cm, 6 cm.

We have

$5^2+6^2=25+36=61,\\\\14^2=196.$

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 : 8 in., 12 in., 20 in.

We have

$8^2+12^2=64+144=208,\\\\20^2=400.$

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 : 10 mm, 20 mm, 30 mm.

We have

$10^2+20^2=100+400=500,\\\\30^2=900.$

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 : 12 ft, 16 ft, 20 ft.

We have

$12^2+16^2=144+256=400,\\\\20^2=400.$

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0

3 years ago

Read 2 more answers

Find the value of<br> 3a²-4ab-26² when A= -1 and b-4

nata0808 [166]

Answer:

-657

Step-by-step explanation:

$a= -1\\b= 4\\$

Substituting the value of a and b

$3a^{2}-4ab-26^{2} \\3(-1)^{2} -4(-1)(4)-676\\3-4(-4)-676\\3+16-676\\19-676\\-657$

The value of 3a²-4ab-26² is -657

4 0

3 years ago